从打字稿中的对象数组中获取属性值的数组

时间:2019-03-19 00:14:33

标签: arrays typescript

class Test{
    constructor(private Name: string, private Id: number, private isAlive: boolean){}

    array1?: string[];
}

想象一下 数组使用API​​响应中的一堆数据初始化。我有一组测试对象。我现在需要的是将该数组中所有这些对象的名称提取到一个新数组中。 我找不到用于此问题的打字稿语法。

3 个答案:

答案 0 :(得分:0)

  

我现在需要的是将该数组中所有这些对象的名称提取到一个新数组中

使用Array.prototype.maphttps://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

修复

Name[]中,您想要string[]

const array1: string[] = names.map(x=>x.fieldThatIsTheStringYouWant);

答案 1 :(得分:0)

Typescript(或多或少)是javascript的超集。同样的Javascript解决方案也适用于Typescript。

const output = input.map( item => item.name );

答案 2 :(得分:0)

  var originalObject = [
        {"first":"Gretchen","last":"Kuphal","email":"greenwolf54@gmail.com","address":"416 
                            Lesch Road","created":"March 1, 2012","balance":"$9,782.26"}];

1。您只想复制数组

var duplicateObject = originalObject;

  1. 如果您想循环播放
  2. 如果要访问一个值,只需执行此操作

duplicateObject[0].first

alert(duplicateObject[0].first);

Editrd 这也可以做到

var originalObject = [
  {"first":"Gretchen","last":"Kuphal","email":"greenwolf54@gmail.com","address":"416 Lesch Road","created":"March 1, 2012","balance":"$9,782.26"},
{"first":"Morton","last":"Mayer","email":"salmonsquirrel25@gmail.com","address":"1602 Bernhard Parkway","created":"April 29, 2017","balance":"$6,596.11"},
{"first":"Catalina","last":"Daugherty","email":"Catalina.Daugherty@filomena.name","address":"11893 Kali Vista","created":"October 16, 2008","balance":"$6,372.86"},
{"first":"Orpha","last":"Heaney","email":"turquoisewolf22@gmail.com","address":"8090 Chris Stream","created":"November 21, 2015","balance":"$9,596.26"},
{"first":"Reva","last":"Mohr","email":"Reva.Mohr@oda.net","address":"0291 Kailyn Stravenue","created":"November 6, 2014","balance":"$4,768.37"},
{"first":"Loma","last":"Keeling","email":"turquoisegiraffe09@gmail.com","address":"84460 Samson Knoll","created":"June 13, 2017","balance":"$9,361.16"}
];

var duplicateObject=new Array(); 

for (let num of originalObject) {
    duplicateObject.push(num.first);
}
// print
for (let first of duplicateObject) {
    console.log(first);
}
相关问题