将列表添加到DF列

Question

我正在尝试将买入信号的负收盘价作为代码的一部分。通常，当我将列添加到DF时，我会执行df [“ ColName”] = buyList，它可以根据我的需要完美运行。但是，由于某种原因，希望您可以帮助我编写此代码，从而产生以下结果。

不是将单个值放在单元格中，而是整个列表。但这不是针对信号列表执行的操作 谁能为我阐明一下？ 如何将清单buyList变成df中的一列

signalList = []
buyList = []
sellList = []
for x,i in enumerate(df["Crossover"]):
    if i == True:
        if df['EMA ' + str(emaShort)].iloc[x] > df['EMA ' + str(emaLong)].iloc[x]:
            signal = "Buy"
            signalList.append(signal)
            buy = -df["Close"]
            buyList.append(buy)
            sell = 0
            sellList.append(sell)
        elif df['EMA ' + str(emaShort)].iloc[x] < df['EMA ' + str(emaLong)].iloc[x]:
            signal = "Sell"
            signalList.append(signal)
            buy = 0
            buyList.append(buy)
            sell = df["Close"]
            sellList.append(sell)
        elif df['EMA ' + str(emaShort)].iloc[x] == df['EMA ' + str(emaLong)].iloc[x]:
            print(df.iloc[x])
            print(x)
            print("******^^^^^^")
    elif i != True:
        signal = "None"
        signalList.append(signal)
        buy = 0
        buyList.append(buy)
        sell = 0
        sellList.append(sell)

df["Signal"] = signalList


df["Long Position"] = buyList