我正在尝试编写一个简单的代码来帮助我跟踪玩纸牌游戏时的玩家姓名和分数。
import pandas as pd
print('Willkommen zum Punkterechner!')
#asking for number of players
p_count = int(input("Anzahl der Spieler?: "))
p_list = []
points = [0]*p_count
#asking for name of players in range of number of players
for i in range(p_count):
p_name = input('Wie lautet der Name von Spieler ' + str(i+1) + '?: ')
p_list.append(p_name)
d = {'Spieler': p_list, 'Punkte': points}
df = pd.DataFrame(data=d)
print(df)
current_round = 1
for i,j in enumerate(p_list):
points_round = int(input('Punkte für ' + j + ' in Runde ' + str(current_round) + ': '))
points[i] += points_round
print(df)
现在,我需要帮助找到一种方法来汇总每个回合/每个球员的积分。我还想继续更新current_round,直到类似input('Keep Playing?')
的内容为'No'。
有什么想法吗?
谢谢
答案 0 :(得分:1)
我将您的字典d
设置为以玩家ID为键,以点为值,例如:
d = {k: v for k,v in zip(p_list, points)}
然后,当ID为j
的玩家“得分”为n
时,您可以进行d[j] += n
这是您的游戏设置方式(您可能知道如何做以打印漂亮的数据框而不是我的代码中的原始字典)。我添加了一些示例代码来处理其他可选回合。
import pandas as pd
import operator
print('Willkommen zum Punkterechner!')
#asking for number of players
p_count = int(input("Anzahl der Spieler?: "))
p_list = range(1, p_count+1)
points = [0]*p_count
d = {k: v for k,v in zip(p_list, points)}
def play_round(current_round=1):
for player in d.keys():
points_round = int(input('Punkte für ' + str(player) + ' in Runde ' + str(current_round) + ': '))
d[player] += points_round
print(d)
if input('Noch ein Spiel?') == 'Nein':
winner = max(d.items(), key=operator.itemgetter(1))[0]
print(f'Der Gewinner ist {winner} mit {d[winner]} Punkten!')
return
else:
play_round(current_round+1)
play_round()