Question

我有一个阵列音轨，位于另一个称为专辑的阵列中。我有以下代码，该代码允许用户输入albums[index]，如果存在，则允许用户输入tracks[index]。如果还存在，则会打印出出现在这些索引处的专辑和曲目。

但是，当我运行代码时，没有得到专辑名称和曲目名称，而是得到以下输出：

The selected track is The selected track is #<Track:0x2fca360> #<Album:0x2fca960>

以下是相关的代码段：

def play_selected_track(albums,tracks)
  # ask user to enter ID number of an album in the albums-list

  puts "Enter album id:"
  album_id = gets.chomp
  index = 0

  while (index<albums.length)
    if (album_id=="#{index}")
      puts "Please enter track id:"
      track_id = gets.chomp
      j = 0
      while (j<tracks.length)

        if (track_id == "#{j}")
          puts "The selected track is " + tracks[j].to_s + " " + albums[index].to_s
        end
        j += 1
      end 
    end 
    index += 1
  end 
end

def main
  # fix the following two lines
  music_file = File.new("albums.txt", "r")
  albums = read_albums_file(music_file)
  tracks = read_tracks(music_file)
  print_albums(albums)
  music_file.close()
  play_selected_track(albums,tracks)
end

Answer 1

默认情况下，#to_s返回对象的类名和对象ID https://apidock.com/ruby/Object/to_s

如果为#to_s和Tack实现自己的Album方法，那么您将获得正确的结果。

class Track
  def to_s
    name
  end
end

class Album
  def to_s
    name
  end
end

最好是显式调用#name。 puts "The selected track is " + tracks[j].name + " " + albums[index].name

打印出数组会产生奇怪的输出

1 个答案: