Question

我有这个字符串a:10,b:xx,e:20,m:xy,w:30,z:50

但是，键和值会改变......

我想将其转换为objective-c中的结构（我希望应用程序自动将字符串转换为结构，而不是手动）

在PHP中，结果将是：

 $array = array(
      'a' => 10, // or 'a' => "10" (doesn't matter)
      'b' => "xx",
      'e' => 20, // or 'e' => "20" (doesn't matter)
      'm' => "xy",
      'w' => 30, // or 'w' => "30" (doesn't matter)
      'z' => 50  // or 'z' => "50" (doesn't matter)
 );

那么，如何将该字符串转换为结构并获得结果，如在PHP示例中，但是在objective-c中进行...？

请告诉我确切的代码，我是objective-c的新手：）

谢谢

Answer 1

PHP结构对我来说看起来更像是一本字典，所以我假设它是。

NSString *s = @"a:10,b:xx,e:20,m:xy,w:30,z:50";
NSArray *pairs = [s componentsSeparatedByString:@","];
NSMutableArray *keys = [NSMutableArray array];
NSMutableArray *values = [NSMutableArray array];

for (NSString *pair in pairs)
{
    NSArray *keyValue = [pair componentsSeparatedByString:@":"];
    [keys addObject:[keyValue objectAtIndex:0]];
    [values addObject:[keyValue objectAtIndex:1]];
}

NSDictionary *dict = [NSDictionary dictionaryWithObjects:values forKeys:keys];
NSLog(@"%@", dict);

这显然非常冗长，但它需要一些奇特的字符串操作。

输出如下：

{
    a = 10;
    b = xx;
    e = 20;
    m = xy;
    w = 30;
    z = 50;
}

Answer 2

你可以爆炸字符串，再次爆炸片段并将所有内容放入字典中。这应该有效：

NSMutableDictionary *dict = [NSMutableDictionary dictionary];
NSString *str = @"a:10,b:xx,e:20,m:xy,w:30,z:50";
NSArray *arr = [str componentsSeparatedByString:@","];
for (NSString *fragment in arr) {
    NSArray *keyvalue = [fragment componentsSeparatedByString:@":"];
    [dict setObject:[keyvalue objectAtIndex:0] forKey:[keyvalue objectAtIndex:1]];
}

Answer 3

NSString* myString = @"a:10,b:xx,e:20,m:xy,w:30,z:50";

使用以下 NSString 的方法。

- (NSArray *)componentsSeparatedByString:(NSString *)separator

NSArray* myArray = [myString componentsSeparatedByString:@","];
NSMutableDictionary *myDictionary = [NSMutableDictionary dictionary];
for (NSString* stringObj in myArray) 
{
     NSArray *myTemp1 = [stringObj componentsSeparatedByString:@":"];
    [myDictionary setObject:[myTemp1 objectAtIndex:0] forKey:[myTemp1 objectAtIndex:1]];
}

现在 myDictionary 实例相当于 $ array

将字符串转换为objective-c中的结构

3 个答案: