我正在开发Android LBS应用程序。我想通过我的应用程序随机调用函数。
我有以下代码。
public class DialANumber extends Activity {
EditText mEditText_number = null;
LinearLayout mLinearLayout_no_button = null;
Button mButton_dial = null;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mLinearLayout_no_button = new LinearLayout(this);
mEditText_number = new EditText(this);
mEditText_number.setText("5551222");
mLinearLayout_no_button.addView(mEditText_number);
mButton_dial = new Button(this);
mButton_dial.setText("Dial!");
mLinearLayout_no_button.addView(mButton_dial);
mButton_dial.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
performDial();
}
});
setContentView(mLinearLayout_no_button);
}
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_CALL) {
performDial();
return true;
}
return false;
}
public void performDial(){
if(mEditText_number!=null){
try {
startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + mEditText_number.getText())));
} catch (Exception e) {
e.printStackTrace();
}
}//if
}
}
我想随机调用performDial()
方法。
答案 0 :(得分:0)
虽然我仍然不确定我完全理解你的问题,但你可以这样做:
double rand = Math.random();
if( rand < 0.2 )
firstFunction();
else if( rand < 0.4 )
secondFunction();
else if( rand < 0.6 )
thirdFunction();
else if( rand < 0.8 )
fourthFunction();
else
fifthFunction();
(Math.random()
生成大于或等于0.0且小于1.0的随机双精度数。