Question

我是新手。我有一个Triangle类，它接收3个格式为[x，y]的列表变量：a，b和c。如何返回带有三角形笛卡尔点的字符串？

 class Triangle():
    def __init__(self, a, b, c):
        """
        Constructor for Vec4
        Expects points as arrays in the form of [x, y].
        All coordinates are given as cartesian coordinates.
        """
        self.a = a
        self.b = b
        self.c = c


def __str__(self):
    """
    Returns a string representation of the triangle. The string is formatted as follows:

    Point A: 0.00 0.00
    Point B: 0.00 0.00
    Point C: 0.00 0.00

    """
    return ""

Answer 1

这是我的实现以及如何实现。您可以返回字符串，并记住将整数转换为字符串。

class Triangle():
    def __init__(self, a, b, c):
        """
        Constructor for Vec4
        Expects points as arrays in the form of [x, y].
        All coordinates are given as cartesian coordinates.
        """
        self.a = a
        self.b = b
        self.c = c


    def __str__(self):
        """
        Returns a string representation of the triangle. The string is formatted as follows:

        Point A: 0.00 0.00
        Point B: 0.00 0.00
        Point C: 0.00 0.00

        """
        return "Point A: " + str(self.a[0]) + " " + str(self.a[1]) + "\nPoint B: " + str(self.b[0]) + " " + str(self.b[1]) + "\nPoint C: " + str(self.c[0]) + " " + str(self.c[1])

t = Triangle([5,4], [1,2], [7,9])
print(t)

输出：

Point A: 5 4
Point B: 1 2
Point C: 7 9

Answer 2

假设一个点是一个像（1.5，6.7）之类的元组

代码如下：

class Triangle():
def __init__(self, a, b, c):
    """
    Constructor for Vec4
    Expects points as arrays in the form of [x, y].
    All coordinates are given as cartesian coordinates.
    """
    self.a = a
    self.b = b
    self.c = c


def __str__(self):
    """
    Returns a string representation of the triangle. The string is formatted as follows:

    Point A: 0.00 0.00
    Point B: 0.00 0.00
    Point C: 0.00 0.00

    """
    return f"Point A: {self.a[0]} {self.a[1]}\nPoint B: {self.b[0]} {self.b[1]}\nPoint C: {self.c[0]} {self.c[1]}"

您可以使用以下方法进行检查：

t = Triangle((2.34,4.62), (6.7,8.52), (9.34,3.32))
print(t)

Answer 3

我建议添加一个新方法，该方法返回三角形的单个点的表示形式。这样，您可以在__str__方法中使用它，并且代码将更少冗余和更简洁。

class Triangle():
    def __init__(self, a, b, c):
        """
        Constructor for Vec4
        Expects points as arrays in the form of [x, y].
        All coordinates are given as cartesian coordinates.
        """
        self.a = a
        self.b = b
        self.c = c

    def point_repr(self, p):
        """
        Make a string representation of a point 'p', and return it.

        p: list of the form [x, y].
        """
        coords = "{0} {1}".format(*p)
        # OR
        coords = "{} {}".format(p[0], p[1])
        return coords


    def __str__(self):
        """
        Returns a string representation of the triangle. The string is formatted as follows:

        Point A: 0.00 0.00
        Point B: 0.00 0.00
        Point C: 0.00 0.00

        """

        template = "Point {}: {}"

        a = self.point_repr(self.a)
        b = self.point_repr(self.b)
        c = self.point_repr(self.c)

        point_a = template.format("A", a)
        point_b = template.format("B", b)
        point_c = template.format("C", c)

        formatted = "{}\n{}\n{}".format(point_a, point_b, point_c)

        return formatted

直角坐标的三角形

3 个答案: