我在通过中断从uart2接收数据时遇到问题。 我正在使用ST32F411VET,为了进行测试,我使用CubeMX创建了一个特定项目。 我已经将USB FTDI转换器从我的PC连接到STM板。 在轮询模式下,我可以发送和接收数据,但是会丢失一些字节。 而且,阻止模式对我不利。 然后,我决定使用中断模式,但是我可以将数据从STM发送到PC,但不会从PC接收任何字节。 这是代码: main.c
#include "main.h"
__root uint16_t i;
uint8_t rx_buffer[256];
UART_HandleTypeDef huart2;
void SystemClock_Config(void);
static void MX_GPIO_Init(void);
static void MX_USART2_UART_Init(void);
int main(void)
{
HAL_Init();
SystemClock_Config();
MX_GPIO_Init();
MX_USART2_UART_Init();
HAL_UART_Transmit(&huart2, (uint8_t*)"Ready...\r\n", 10, 100);
HAL_UART_Receive_IT(&huart2, (uint8_t *)rx_buffer, 4);
while (1) {}
}
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart)
{
HAL_UART_Receive_IT(&huart2, (uint8_t *)rx_buffer, 4);
i++;
}
void SystemClock_Config(void)
{
RCC_OscInitTypeDef RCC_OscInitStruct = {0};
RCC_ClkInitTypeDef RCC_ClkInitStruct = {0};
__HAL_RCC_PWR_CLK_ENABLE();
__HAL_PWR_VOLTAGESCALING_CONFIG(PWR_REGULATOR_VOLTAGE_SCALE1);
RCC_OscInitStruct.OscillatorType = RCC_OSCILLATORTYPE_HSI;
RCC_OscInitStruct.HSIState = RCC_HSI_ON;
RCC_OscInitStruct.HSICalibrationValue = RCC_HSICALIBRATION_DEFAULT;
RCC_OscInitStruct.PLL.PLLState = RCC_PLL_NONE;
if (HAL_RCC_OscConfig(&RCC_OscInitStruct) != HAL_OK)
{
Error_Handler();
}
RCC_ClkInitStruct.ClockType = RCC_CLOCKTYPE_HCLK|RCC_CLOCKTYPE_SYSCLK
|RCC_CLOCKTYPE_PCLK1|RCC_CLOCKTYPE_PCLK2;
RCC_ClkInitStruct.SYSCLKSource = RCC_SYSCLKSOURCE_HSI;
RCC_ClkInitStruct.AHBCLKDivider = RCC_SYSCLK_DIV1;
RCC_ClkInitStruct.APB1CLKDivider = RCC_HCLK_DIV1;
RCC_ClkInitStruct.APB2CLKDivider = RCC_HCLK_DIV1;
if (HAL_RCC_ClockConfig(&RCC_ClkInitStruct, FLASH_LATENCY_0) != HAL_OK)
{
Error_Handler();
}
}
static void MX_USART2_UART_Init(void)
{
huart2.Instance = USART2;
huart2.Init.BaudRate = 115200;
huart2.Init.WordLength = UART_WORDLENGTH_8B;
huart2.Init.StopBits = UART_STOPBITS_1;
huart2.Init.Parity = UART_PARITY_NONE;
huart2.Init.Mode = UART_MODE_TX_RX;
huart2.Init.HwFlowCtl = UART_HWCONTROL_NONE;
huart2.Init.OverSampling = UART_OVERSAMPLING_16;
if (HAL_UART_Init(&huart2) != HAL_OK)
{
Error_Handler();
}
}
static void MX_GPIO_Init(void)
{
__HAL_RCC_GPIOD_CLK_ENABLE();
}
void Error_Handler(void)
{
}
#ifdef USE_FULL_ASSERT
void assert_failed(uint8_t *file, uint32_t line)
{
}
#endif /* USE_FULL_ASSERT */
并且GPio设置为 stm32f4xx_hal_msp.c
void HAL_UART_MspInit(UART_HandleTypeDef* huart)
{
GPIO_InitTypeDef GPIO_InitStruct = {0};
if(huart->Instance==USART2)
{
__HAL_RCC_USART2_CLK_ENABLE();
__HAL_RCC_GPIOD_CLK_ENABLE();
PD5 ------> USART2_TX
PD6 ------> USART2_RX
GPIO_InitStruct.Pin = GPIO_PIN_5|GPIO_PIN_6;
GPIO_InitStruct.Mode = GPIO_MODE_AF_PP;
GPIO_InitStruct.Pull = GPIO_NOPULL;
GPIO_InitStruct.Speed = GPIO_SPEED_FREQ_VERY_HIGH;
GPIO_InitStruct.Alternate = GPIO_AF7_USART2;
HAL_GPIO_Init(GPIOD, &GPIO_InitStruct);
HAL_NVIC_SetPriority(USART2_IRQn, 0, 0);
HAL_NVIC_EnableIRQ(USART2_IRQn);
}
}
我一直在寻找解决方案,但是没有运气。 你能帮助我吗? 谢谢。
答案 0 :(得分:0)
为什么您有一个花费4的约会缓冲区?
HAL_UART_Receive_IT(&huart2, (uint8_t *)rx_buffer, 4);
尝试一次获取一个字符并将其分析并将其添加到数组中。
HAL_UART_Receive_IT(&huart2, (uint8_t *)rx_buffer, 1);
尝试这个例子
uint8_t rx_data = 0;
uint8_t rx_buffer[256];
int rx_index = 0;
HAL_UART_Receive_IT(&huart2, &rx_data, 1);
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart) {
if (huart == &huart2) {
if (rx_buffer != '\n'){
rx_buffer[rx_index++] = rx_data;
}else{
YouFun((char *) rx_buffer);
rx_index = 0;
memset(rx_buffer, 0, sizeof(rx_buffer));
}
HAL_UART_Receive_IT(&huart2, &rx_data, 1); // activate receive
}
}