获得对线程的控制然后将其杀死

时间:2011-05-30 11:50:41

标签: java multithreading

我对Java中的线程有疑问。在我的代码中,

...
client.doSth();
// now need to get hold of the thread that is initiated by 'client'
(get a reference to the 'client' thread)
// now kills it
(kills the 'client' thread)
...

所以我想知道的是:在第一个括号中,我如何以编程方式获取对'client'线程的引用(不是程序运行的主线程),在第二个括号中,如何正确杀死它,即不使用折旧的stop()方法。

非常感谢。

5 个答案:

答案 0 :(得分:2)

要显示Thread树,请执行以下操作:

你可以这样做:

// Find the root thread group
ThreadGroup root = Thread.currentThread().getThreadGroup().getParent();
while (root.getParent() != null) {
    root = root.getParent();
}

// Visit each thread group
visit(root, 0);

// This method recursively visits all thread groups under `group'.
public static void visit(ThreadGroup group, int level) {
    // Get threads in `group'
    int numThreads = group.activeCount();
    Thread[] threads = new Thread[numThreads*2];
    numThreads = group.enumerate(threads, false);

    System.out.println("    ");

    // Enumerate each thread in `group'
    for (int i=0; i<numThreads; i++) {
        // Get thread
        Thread thread = threads[i];
        System.out.println(thread.toString());
    }

    // Get thread subgroups of `group'
    int numGroups = group.activeGroupCount();
    ThreadGroup[] groups = new ThreadGroup[numGroups*2];
    numGroups = group.enumerate(groups, false);

    // Recursively visit each subgroup
    for (int i=0; i<numGroups; i++) {
        visit(groups[i], level+1);
        }

}

您可以选择调用显示指定Thread ID的stackTrace的方法:

 System.out.println(thread.dumpStack());

现在你有要杀死的id:

int idToKill = 2;
int active = Thread.activeCount();
System.out.println("currently active threads: " + active);
Thread all[] = new Thread[active];
Thread.enumerate(all);
for (int i = 0; i < active; i++) {
  System.out.println(i + ": " + all[i]);
  if(idToKill == i)
    ((Thread) all[i]).interrupt();
}

答案 1 :(得分:1)

你可以在你的客户端创建一个stpSth()方法并调用它来阻止它

public class Client(){
    private Thread t;
    volatile private boolean stop;//volatile to ensure visibility across threads
    public doSth(){
        stop=false;
        Runnable r = new Runnable(){
            @Override
            public void run(){
                while(!stop){
                    //do stuff and periodically and ensure that interrupts bubble through
                }
            }
        };

        t = new Thread(r);
        t.start();
    }

    public void stopSht(){
         stop=true;
         t.interupt();
    }
}

答案 2 :(得分:1)

编辑: 重新阅读问题后,如果您有权访问客户端代码,我不再确定。如果你这样做,你可以修改它,甚至不使用线程,但java.util.concurrent.ExecutorService或类似的......但

由于代码不是您自己的......您可以自行阻止代码。

ThreadGroup类是专为。管理部分程序或模块并不容易,通常需要一些已经建立的框架。确保一些第三方代码会表现得很好并且并不总是可行的。它应该包括上下文类加载器,什么不是,但这里是一个如何完成它的脱脂版本。

仍然可能有一些事情可以打破入侵者的骨头。假设已经使用了stop()/ close()等,在日志记录期间会有一些像ThreadDeath这样的技巧,等等。

ThreadGroup g=new ThreadGroup("client X group");

Runnable r=new Runnable(){
public void run(){
  client.doSmth();//assuming a new thread is started...
}
}
Thread t= new Thread(g, r, "clientStarter");
t.start();

 //stopping, last resort code, it's usually more complicated than just thread.stop, though

//now you can enumerate threads of the ThreadGroup
synchronized(g){//sync ensures no more threads will be created, use it w/ extreme caution
  Thread[] threads = new Thread[g.activeCount()];
  for(Thread thread:threads){
    if(thread==null) break;
    thread.stop();//
  //cannot join in sync of ThreadGroup, do not use it here
    }
  }
祝你好运!

答案 3 :(得分:1)

我在comment中看到您使用的是kryonet API。

kryonet为Client对象提供了stop()方法。如果使用start()启动客户端创建一个Thread,stop()应该停止它。

以下是启动和停止kryonet服务器和客户端的代码段,显示进程中各个点的活动线程。 2秒钟的睡眠是让线程在请求​​停止时结束。

import java.io.IOException;
import java.util.Arrays;

import com.esotericsoftware.kryonet.Client;
import com.esotericsoftware.kryonet.Server;

public class KryonetAndThreads {
    public static void main(String[] args) throws IOException,
            InterruptedException {
        Server s = new Server();
        s.start();
        s.bind(1927);
        printThreads("server started");

        Client c = new Client();
        c.start();
        c.connect(5000, "LOCALHOST", 1927);
        printThreads("client connected");
        Server s1 = s;
        s.stop();
        printThreads("server stopped");

        s = new Server();
        s.start();
        s.bind(1928);
        printThreads("new server started"); // new server thread will be last on
                                            // the list.

        c.stop();
        printThreads("client stopped");

        c.start();
        c.connect(5000, "localhost", 1928);
        printThreads("client connected to second server");

        c.stop();
        s.stop();
        s1.stop();
        printThreads("both stopped");
    }

    private static void printThreads(String message)
            throws InterruptedException {
        // tick:
        Thread.sleep(2000L);
        Thread[] threads = new Thread[Thread.activeCount()];
        Thread.enumerate(threads);
        System.out.println(message + " :  " + Arrays.asList(threads));
    }
}

答案 4 :(得分:0)

如果doSth()方法返回Thread对象,则可以执行以下操作;

Thread t = client.doSth();
t.interrupt();