第一次学习django。想要生成这样的网址-example.com/category,pk,title
目前,我只能生成此内容-example.com/pk,title
这是我的模特。py
path(
"<str:slug0>,<int:pk>,<str:slug1>",
ArticlePkAndSlugDetailView.as_view(),
name="article-pk-slug-detail",
),
urls.py
Exception Type: NoReverseMatch at /django- blog/
Exception Value: Reverse for 'article-pk-slug-detail' with keyword arguments '{'slug0': 'offer', 'pk': 4, 'slug1': ''}' not found. 1 pattern(s) tried: ['supercar\\/(?P<slug0>[^/]+)\\,(?P<pk>[0-9]+)\\,(?P<slug1>[^/]+)$']
我得到了这个范围来学习新知识:
const result = unwantedWords.reduce((prev, current)=>prev.replace(current,''), givenString);
我尝试过哪些菜鸟菜?救救我!