让一个函数调用另一个创建元组的函数

Question

我正试图让我的results函数调用我的retrieve_pub_vote_summary函数，该函数创建一个元组。然后，我希望我的结果函数打印出元组。

@application.route('/results/')
def results:
    publication = "nytimes"
    retrieve_pub_vote_summary(publication)
    print(pub_tuple)

##############################################
def retrieve_pub_vote_summary(publication):
    onevotes = 1
    twovotes = 2
    pub_tuple = (onevotes, twovotes)
    print(pub_tuple)
    return pub_tuple

pub_tuple在retrieve_pub_vote_summary中可以正常打印。但这似乎没有结果。我收到“ NameError：未定义名称'pub_tuple'。”

Answer 1

您的代码中有2个错误：

def results():                                          # added ()
    publication = "nytimes"
    pub_tuple = retrieve_pub_vote_summary(publication)  # assign the result
    print(pub_tuple)                                    # now pub_tuple is defined the line above


##############################################
def retrieve_pub_vote_summary(publication):
    onevotes = 1
    twovotes = 2
    pub_tuple = (onevotes, twovotes)
    print(pub_tuple)
    return pub_tuple


results()   # call results

现在它返回

(1, 2)
(1, 2)

retrieve_pub_vote_summary 中的

pub_tuple 是retrieve_pub_vote_summary中的局部变量。这就是为什么无法打印它并导致错误的原因。