Question

假设我有以下表格 -

smallville=# create table contacts (name varchar(16), address_id int); 
CREATE TABLE
smallville=# create table addresses (address_id int, address varchar(16));
CREATE TABLE
smallville=# create table partners (name1 varchar(16), name2 varchar(16));
CREATE TABLE

smallville=# insert into contacts values ('Clark Kent', NULL), ('Loise Lane', 1);
INSERT 0 2
smallville=# insert into addresses values (1, 'Manhattan'), (2, 'North Pole');
INSERT 0 2
smallville=# insert into partners values ('Clark Kent', 'Loise Lane'),
             ('Loise Lane', 'Clark Kent') ; 
INSERT 0 2

我可以获得姓名和地址 -

smallville=# select c.name, a.address from contacts c
             left outer join addresses a
             on c.address_id = a.address_id ; 
    name    |  address  
------------+-----------
 Clark Kent | (NULL)
 Loise Lane | Manhattan
(2 rows)

但是如何获得以下内容，即如果某个地址丢失，则显示他/她的伴侣地址？ -

    name    |  address  
------------+-----------
 Clark Kent | Manhattan
 Loise Lane | Manhattan
(2 rows)

感谢。

Answer 1

select c.name, coalesce(a.address, a1. address) from contacts c
left outer join addresses a on c.address_id = a.address_id 
left outer join partners on c.name=partners.name1 
left outer join contacts c1 on c1.name=partners.name2 
left outer join addresses a1 on c1.address_id = a1.address_id;

PostgreSQL条件加入

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