Question

我对此查询有点挣扎，我有下表：

setting
-------
id  | name   | value   | type
--------------------------------
1   | title  | Hi      | string
2   | color  | #ff0000 | string

user_setting
-------
id | userId | settingId | value
--------------------------------
1  | 1      | 1         | Hello

user
-------
id | email
1  | foo@test.com

我想运行一个查询，该查询将为用户1选择所有设置，但还包括默认值，因此理想情况下，我得到以下信息：

id    | default | value
-----------------------
title | Hi      | Hello
color | #ff0000 | null

我当前的查询是

SELECT  setting.id, setting.name, setting.value,  user_setting.value, user.id
FROM setting
RIGHT JOIN user_setting
    ON setting.id = "user_setting"."settingId"
LEFT OUTER JOIN user
    ON "user_setting"."userId" = user.id
WHERE user.id = 1

但这只会给我用户定义的值。

编辑：更新了设置表

Answer 1

user_settings.setting_id

否则select s.name, s.value as default, us.value from setting s left join user_setting us on us.setting_id = s.id and us.user_id = 1不会引用任何内容。使用此列，您需要：

 const options: CameraOptions = {
    quality: 10
    , destinationType: this.camera.DestinationType.DATA_URL
    , mediaType: this.camera.MediaType.PICTURE // Try this
    , sourceType: this.camera.PictureSourceType.PHOTOLIBRARY
 };

SQL条件连接，带默认值

1 个答案: