Question

我有69台机器，每台机器都有12个月的生产数据。

我使用groupby.plot（）将它们全部绘制出来，并获得了一长串视图。想知道如何进行紧凑的布局以便我可以一次查看它们吗？想要的结果是每行有7列和69/7行。请帮忙！

c1.groupby('System ID').plot(x='Month', y='Monthly Production',kind='bar',legend=True)

Answer 1

这是我的最终答案。

# We can ask for ALL THE AXES and put them into axes
fig, axes = plt.subplots(nrows=10, ncols=7, sharex=True, sharey=False, figsize=(20,15))
axes_list = [item for sublist in axes for item in sublist] 

ordered_systems = grouped['Monthly Production'].last().sort_values(ascending=False).index

# Now instead of looping through the groupby
# you CREATE the groupby
# you LOOP through the ordered names
# and you use .get_group to get the right group
grouped = c1.groupby("System ID")

first_month = c1['Month'].min()
last_month = c1['Month'].max()

for system in ordered_systems:
    selection = grouped.get_group(system)

    ax = axes_list.pop(0)
    selection.plot(x='Month', y='Monthly Production', label=system, ax=ax, legend=False)
    selection.plot(x='Month', y='Monthly Usage',secondary_y=True, ax=ax, legend=False)
    ax.set_title(system)
    ax.tick_params(
        which='both',
        bottom='off',
        left='off',
        right='off',
        top='off'
    )
    ax.grid(linewidth=0.25)
    ax.set_xlim((first_month, last_month))
    ax.set_xlabel("")
    ax.set_xticks((first_month, last_month))
    ax.spines['left'].set_visible(False)
    ax.spines['top'].set_visible(False)
    ax.spines['right'].set_visible(False)

# Now use the matplotlib .remove() method to 
# delete anything we didn't use
for ax in axes_list:
    ax.remove()

plt.subplots_adjust(hspace=1)

plt.tight_layout()

Answer 2

我想我会添加一个使用seaborn的示例，因为在这种情况下它可能很有用，因为用它来按列包装内容非常容易。我希望有人可以提供更好的答案，也许可以使用熊猫，我希望他们能提供更好的答案。

import seaborn as sns
import pandas as pd
import numpy as np

np.random.seed(1)

N = 2000

df = pd.DataFrame(np.random.randint(0,4, (N,7)))
df['system'] = np.random.randint(0, 69, N )

其中df为；

      0  1  2  3  4  5  6  system
674   1  2  3  1  0  0  0      15
1699  0  0  1  3  0  0  1       9
1282  0  0  0  0  1  0  2      47
1315  0  3  1  3  1  1  1      37
1210  1  1  0  3  1  3  1      11

在绘制之前将数据融化：

df_plot = df.melt(id_vars='system')

看起来像


       system variable  value
8756       23        4      2
5474       24        2      2
11242      12        5      2
7820       56        3      3

然后

sns.catplot(x = 'variable', y = 'value', col = 'system', 
    hue = 'variable', dodge = False,
    col_wrap = 6, data = df_plot, kind = 'bar', ci = False)

熊猫Groupby地块布局

2 个答案: