Question

这是使用反射更新属性的最快方法吗？假设该属性始终为int：

PropertyInfo counterPropertyInfo = GetProperty();
int value = (int)counterPropertyInfo.GetValue(this, null);
counterPropertyInfo.SetValue(this, value + 1, null);

Answer 1

当你知道类型参数时，我做了一些benchmarking here（非泛型方法不会非常不同）。如果您无法直接访问该属性，CreateDelegate将是最快的方法。使用CreateDelegate，您可以直接处理GetGetMethod的{{1}}和GetSetMethod，因此每次都不会使用反射。

PropertyInfo

所以现在你打电话：

public static Func<S, T> BuildGetAccessor<S, T>(Expression<Func<S, T>> propertySelector)
{
    return propertySelector.GetPropertyInfo().GetGetMethod().CreateDelegate<Func<S, T>>();
}

public static Action<S, T> BuildSetAccessor<S, T>(Expression<Func<S, T>> propertySelector)
{
    return propertySelector.GetPropertyInfo().GetSetMethod().CreateDelegate<Action<S, T>>();
}

// a generic extension for CreateDelegate
public static T CreateDelegate<T>(this MethodInfo method) where T : class
{
    return Delegate.CreateDelegate(typeof(T), method) as T;
}

public static PropertyInfo GetPropertyInfo<S, T>(this Expression<Func<S, T>> propertySelector)
{
    var body = propertySelector.Body as MemberExpression;
    if (body == null)
        throw new MissingMemberException("something went wrong");

    return body.Member as PropertyInfo;
}

甚至可以更好地将逻辑封装在专用类中，以便在其上设置get和set方法。

类似的东西：

TestClass cwp = new TestClass();
var access = BuildGetAccessor((TestClass t) => t.AnyValue);
var result = access(cwp);

简短而简单。您可以为希望获取/设置的每个“类属性”对携带此类的实例。

用法：

public class Accessor<S>
{
    public static Accessor<S, T> Create<T>(Expression<Func<S, T>> memberSelector)
    {
        return new GetterSetter<T>(memberSelector);
    }

    public Accessor<S, T> Get<T>(Expression<Func<S, T>> memberSelector)
    {
        return Create(memberSelector);
    }

    public Accessor()
    {

    }

    class GetterSetter<T> : Accessor<S, T>
    {
        public GetterSetter(Expression<Func<S, T>> memberSelector) : base(memberSelector)
        {

        }
    }
}

public class Accessor<S, T> : Accessor<S>
{
    Func<S, T> Getter;
    Action<S, T> Setter;

    public bool IsReadable { get; private set; }
    public bool IsWritable { get; private set; }
    public T this[S instance]
    {
        get
        {
            if (!IsReadable)
                throw new ArgumentException("Property get method not found.");

            return Getter(instance);
        }
        set
        {
            if (!IsWritable)
                throw new ArgumentException("Property set method not found.");

            Setter(instance, value);
        }
    }

    protected Accessor(Expression<Func<S, T>> memberSelector) //access not given to outside world
    {
        var prop = memberSelector.GetPropertyInfo();
        IsReadable = prop.CanRead;
        IsWritable = prop.CanWrite;
        AssignDelegate(IsReadable, ref Getter, prop.GetGetMethod());
        AssignDelegate(IsWritable, ref Setter, prop.GetSetMethod());
    }

    void AssignDelegate<K>(bool assignable, ref K assignee, MethodInfo assignor) where K : class
    {
        if (assignable)
            assignee = assignor.CreateDelegate<K>();
    }
}

在这里使用索引器有点不好，你可以用专用的“Get”和“Set”方法替换它，但对我来说非常直观:)）

为避免每次都指定类型，

Person p = new Person { Age = 23 };
var ageAccessor = Accessor<Person>(x => x.Age);
int age = ageAccessor[p]; //gets 23
ageAccessor[p] = 45; //sets 45

我使基础var ageAccessor = Accessor<Person>(x => x.Age); var nameAccessor = Accessor<Person>(x => x.Name); var placeAccessor = Accessor<Person>(x => x.Place);类可实现，这意味着你可以做

Accessor<>

拥有基础var personAccessor = new Accessor<Person>(); var ageAccessor = personAccessor.Get(x => x.Age); var nameAccessor = personAccessor.Get(x => x.Name); var placeAccessor = personAccessor.Get(x => x.Place);类意味着您可以将它们视为一种类型，例如

Accessor<>

Answer 2

你应该看一下FastMember（nuget，source code]，与反思相比真的很快。

我已经测试了这3个实现：

基准测试需要基准功能：

static long Benchmark(Action action, int iterationCount, bool print = true)
{
    GC.Collect();
    var sw = new Stopwatch();
    action(); // Execute once before

    sw.Start();
    for (var i = 0; i <= iterationCount; i++)
    {
        action();
    }

    sw.Stop();
    if (print) System.Console.WriteLine("Elapsed: {0}ms", sw.ElapsedMilliseconds);
    return sw.ElapsedMilliseconds;
}

虚假课程：

public class ClassA
{
    public string PropertyA { get; set; }
}

一些测试方法：

private static void Set(string propertyName, string value)
{
    var obj = new ClassA();
    obj.PropertyA = value;
}

private static void FastMember(string propertyName, string value)
{
    var obj = new ClassA();
    var type = obj.GetType();
    var accessors = TypeAccessor.Create(type);
    accessors[obj, "PropertyA"] = "PropertyValue";
}

private static void SetValue(string propertyName, string value)
{
    var obj = new ClassA();
    var propertyInfo = obj.GetType().GetProperty(propertyName);
    propertyInfo.SetValue(obj, value);
}

private static void SetMethodInvoke(string propertyName, string value)
{
    var obj = new ClassA();
    var propertyInfo = obj.GetType().GetProperty(propertyName);
    propertyInfo.SetMethod.Invoke(obj, new object[] { value });
}

脚本本身：

var iterationCount = 100000;
var propertyName = "PropertyA";
var value = "PropertyValue";

Benchmark(() => Set(propertyName, value), iterationCount);
Benchmark(() => FastMember(propertyName, value), iterationCount);
Benchmark(() => SetValue(propertyName, value), iterationCount);
Benchmark(() => SetMethodInvoke(propertyName, value), iterationCount);

100 000次迭代的结果：

默认设置器：3ms

FastMember：36ms

PropertyInfo.SetValue：109ms

PropertyInfo.SetMethod：91ms

现在你可以选择你的了！

Answer 3

请确保您以某种方式缓存PropertyInfo，以便您不能重复调用type.GetProperty。除此之外，如果您为执行增量的类型的方法创建委托可能会更快，或者像Teoman建议使类型实现接口并使用它。

C＃反思：更新房产价值的最快方法？

3 个答案: