我正在尝试比较字符串的第一个字符,以查看是否匹配,如果要匹配,我想设置剪贴板数据。该字符串来自getclipboard函数,并设置为const char *数据,我尝试将其设置为std :: string,但与此同时出现了另一个错误。 这是我的Clipboard.cpp
#include <iostream>
#include <windows.h>
#include <cstring>
namespace Diall_ClipBoard_catch
{
class ClipBoard
{
private:
::HANDLE dHDat;
::std::string tmpstringsign;
bool isopen;
char* dHbuffer;
char* dHbuffertemp;
char* dNtoken;
public:
ClipBoard(void)
{
this->dHbuffer = const_cast <char*>("");
this->dHbuffertemp = const_cast <char*>("");
this->tmpstringsign = "dnb_4554_2102";
this->isopen = false;
};
~ClipBoard(void)
{
}
char* GetData(void)
{
this->Start();
if (this->isopen)
{
this->dHDat = ::GetClipboardData(CF_TEXT);
if (this->dHDat)
{
this->dHbuffer = (char*)::GlobalLock(this->dHDat);
if (::std::strcmp(this->dHbuffertemp, this->dHbuffer) != 0 && this->dHbuffer != "" && this->dHbuffer != NULL)
{
this->dHbuffertemp = this->dHbuffer;
//::std::cout << this->dHbuffer << "\n";
return this->dHbuffer;
}
::GlobalUnlock(this->dHDat);
}
CloseClipboard();
this->isopen = FALSE;
::Sleep(1000);
}
}
void SetData(void)
{
const char* data = this->dHbuffer;
const char* newstring = "Hello World";
const size_t len = strlen(newstring) + 1;
HGLOBAL hMem = GlobalAlloc(GMEM_MOVEABLE, len);
memcpy(GlobalLock(hMem), newstring, len);
GlobalUnlock(hMem);
if (!OpenClipboard(NULL))
{
return;
}
if (strlen(data) == 8)
{
if(data[0] == "1" || data[0] == "7")
{
EmptyClipboard();
SetClipboardData(CF_TEXT, hMem);
}
}
CloseClipboard();
this->isopen = TRUE;
}
private:
void Start(void)
{
if (!OpenClipboard(NULL))
{
return;
}
this->isopen = true;
}
};
}
这是我的main.cpp
#include "Clipboard.h"
int main()
{
::Diall_ClipBoard_catch::ClipBoard* clipboard = new Diall_ClipBoard_catch::ClipBoard();
int temp1 = 0, temp2 = 0;
EmptyClipboard();
while (1)
{
temp1 = GetClipboardSequenceNumber();
if (temp1!= temp2)
{
clipboard->SetData();
std::cout << clipboard->GetData() << std::endl;
}
temp2 = temp1;
}
return 0;
}
我尝试更改
data[0] = "1"
到
strcmp(data[0], 1) == 0
但是我遇到了同样的错误。
我遇到的另一个问题是,该程序仅运行一次,即仅显示剪贴板的内容,而当我复制其他文本时,则不会显示它。
答案 0 :(得分:2)
TL; DR:更改
if(data[0] == "1" || data[0] == "7")
到
if(data[0] == '1' || data[0] == '7')
data
是char*
,因此用data[0]
取消引用会给您char
。 "1"
是长度为1的字符串(char*
),将导致char
与char*
的无效比较(请参见错误)。
您可能想要的是字符'1'
。我们用单引号表示C ++中的字符文字。