Question

我还要加入2张桌子：T1有一张所有订购物品的清单，T2有一张所有物品的清单。我正在寻找一个结果集，该结果集将显示从T1订购的所有商品的数量以及来自T2的相应发货数量。

当我检查T1的一个订单的日期/订单/项目/数量信息时，它看起来像这样：

DATE                  |ORDER    |ITEM  |DESCRIPTION|QTY|CUSTOMER
01/01/2011 12:00:00 AM|123456789|123456|shoes      |1  |JANE
01/01/2011 12:00:00 AM|123456789|234567|shirt      |2  |TIM
01/01/2011 12:00:00 AM|123456789|345678|pants      |4  |JOE
01/01/2011 12:00:00 AM|123456789|123456|shoes      |9  |BOB

T2看起来像这样：

ORDER    |ITEM  |QTYSHIPPED|SHIPPED
123456789|123456|1         |01/10/2011 12:00:00 PM
123456789|234567|2         |01/10/2011 12:00:00 PM
123456789|345678|4         |01/10/2011 12:00:00 PM
123456789|123456|9         |01/10/2011 12:00:00 PM

我的查询如下：

select convert(varchar,a.date,101) as orderdate, a.order, a.item, a.description, sum(a.qty) as qty_ordered, convert(varchar,b.shipped,101) as shippeddate sum(b.qtyshipped) as qtyshipped
from T1 a --T1 is table with all items ordered
left join shipped T2 --T2 contains order #, qty shipped and shipped date
on a.order = b.order
group by convert(varchar,a.date,101), a.order, a.item, a.description, b.shipped

结果如下：

orderdate|order|item|description|qty_ordered|shippeddate|qtyshipped
01/01/2011|123456789|123456|20|01/10/2011|20
01/01/2011|123456789|234567|4|01/10/2011|20
01/01/2011|123456789|345678|8|01/10/2011|20

我希望看到的结果如下：

orderdate|order|item|description|qty_ordered|shippeddate|qtyshipped
01/01/2011|123456789|123456|10|01/10/2011|20
01/01/2011|123456789|234567|2|01/10/2011|20
01/01/2011|123456789|345678|4|01/10/2011|20

任何信息和帮助将不胜感激！

Answer 1

我认为您还需要加入项目：

on a.order = b.order, a.item = b.item

Answer 2

WITH OrderDays AS (
  SELECT *, OrderDate = DATEADD(day, DATEDIFF(day, 0, DATE), 0)
  FROM T1
),
ShippingDays AS (
  SELECT *, ShippingDate = DATEADD(day, DATEDIFF(day, 0, SHIPPED), 0)
  FROM T2
),
OrdersGrouped AS (
  SELECT
    OrderDate,
    [ORDER],
    ITEM,
    DESCRIPTION,
    Qty = SUM(QTY)
  FROM OrderDays
  GROUP BY OrderDate, [ORDER], ITEM, DESCRIPTION
),
ShippingsGrouped AS (
  SELECT
    ShippingDate,
    [ORDER],
    ITEM,
    QtyShipped = SUM(QTYHSHIPPED)
  FROM OrderDays
  GROUP BY ShippingDate, [ORDER], ITEM
)
SELECT
  o.*,
  s.ShippingDate,
  s.QtyShipped
FROM OrdersGrouped o
  LEFT JOIN ShippingsGrouped s ON o.[ORDER] = s.[ORDER] AND o.ITEM = s.ITEM

在不同日期发生的相同项目发件将分别进行分组（和显示）。如果您希望将它们组合在一起，只需修改上面的ShippingGrouped CTE，如下所示：

…
ShippingsGrouped AS (
  SELECT
    ShippingDate = MAX(ShippingDate),
    [ORDER],
    ITEM,
    QtyShipped = SUM(QTYHSHIPPED)
  FROM OrderDays
  GROUP BY [ORDER], ITEM
)
…

ShippingDate列将包含相应商品的上一个发货日期。

SQL Server 2005/2008 sum（qty）结果在连接时相乘

2 个答案: