数据框:按数据时间索引和列分组

时间:2020-04-18 11:00:15

标签: pandas pandas-groupby python-datetime

我需要按idflag对以下数据帧(df2)进行分组, 累积r1 = {'id':'1', 'date':'2020-01-20', 'flag':1} r2 = {'id':'1', 'date':'2020-01-20', 'flag':1} r3 = {'id':'1', 'date':'2020-01-20', 'flag':1} r4 = {'id':'1', 'date':'2020-01-23', 'flag':1} r5 = {'id':'1', 'date':'2020-01-23', 'flag':1} r6 = {'id':'1', 'date':'2020-01-22', 'flag':1} r7 = {'id':'2', 'date':'2019-11-18', 'flag':1} r8 = {'id':'2', 'date':'2019-11-18', 'flag':1} r9 = {'id':'2', 'date':'2019-11-21', 'flag':1} r10 = {'id':'2', 'date':'2019-11-19', 'flag':1} r11 = {'id':'2', 'date':'2019-11-19', 'flag':1} r12 = {'id':'2', 'date':'2019-11-19', 'flag':1} r13 = {'id':'2', 'date':'2019-11-19', 'flag':1} r14 = {'id':'2', 'date':'2019-11-07', 'flag':1} df2 = pd.DataFrame([r1,r2,r3,r4,r5,r6,r7,r8,r9,r10,r11,r12,r13,r14]) df2 = df2.set_index('date') df2 id flag date 2020-01-20 1 1 2020-01-20 1 1 2020-01-20 1 1 2020-01-23 1 1 2020-01-23 1 1 2020-01-22 1 1 2019-11-18 2 1 2019-11-18 2 1 2019-11-21 2 1 2019-11-19 2 1 2019-11-19 2 1 2019-11-19 2 1 2019-11-19 2 1 2019-11-07 2 1 个值作为计数:

flag

如何获取此结果(df3),其中date是具有相同的idr1 = {'id':'1', 'date':'2020-01-20', 'flag':3} r4 = {'id':'1', 'date':'2020-01-23', 'flag':2} r6 = {'id':'1', 'date':'2020-01-22', 'flag':1} r7 = {'id':'2', 'date':'2019-11-18', 'flag':2} r9 = {'id':'2', 'date':'2019-11-21', 'flag':1} r10 = {'id':'2', 'date':'2019-11-19', 'flag':4} r14 = {'id':'2', 'date':'2019-11-07', 'flag':1} df3 = pd.DataFrame([r1,r4,r6,r7,r9,r10,r14]) df3 = df3.set_index('date') df3 id flag date 2020-01-20 1 3 2020-01-23 1 2 2020-01-22 1 1 2019-11-18 2 2 2019-11-21 2 1 2019-11-19 2 4 2019-11-07 2 1 的值的总和:

StringJoiner

0 个答案:

没有答案