在mvvmLight viewmodel中使用WebContext时出现问题

时间:2011-05-24 21:02:46

标签: .net silverlight mvvm mvvm-light

像往常一样,我正在尝试使用新技术并立即解决问题。

我有一个Silverlight业务应用程序+ MvvmLight。

在我的viewmodel中,我尝试获取登录用户的角色:

    public HomeViewModel()
    {
        if (IsInDesignMode)
        {
            // Code runs in Blend --> create design time data.
        }
        else
        {
            // Code runs "for real"                
            DetermineStartableProcesses();
        }
    }

    private void DetermineStartableProcesses()
    {
        _startableProcesses = new ObservableCollection<WorkflowProcess>(
            WebContext.Current.User.Roles.SelectMany(r =>
                WorkflowProcess.GetStartableByRole(r))
                .Distinct());
    }

在运行时,我遇到了这个例外:

System.Windows.Markup.XamlParseException occurred
  Message=The invocation of the constructor on type 'CompanyHR.ViewModel.ViewModelLocator' that matches the specified binding constraints threw an exception. [Line: 18 Position: 57]
  LineNumber=18
  LinePosition=57
  StackTrace:
       at System.Windows.Application.LoadComponent(Object component, Uri resourceLocator)
       at CompanyHR.App.InitializeComponent()
       at CompanyHR.App..ctor()
  InnerException: System.ArgumentNullException
       Message=Value cannot be null.
Parameter name: source
       StackTrace:
            at System.Linq.Enumerable.SelectMany[TSource,TResult](IEnumerable`1 source, Func`2 selector)
            at CompanyHR.ViewModel.HomeViewModel.DetermineStartableProcesses()
            at CompanyHR.ViewModel.HomeViewModel..ctor()
            at CompanyHR.ViewModel.ViewModelLocator..ctor()
       InnerException: 

看起来ViewModelLocator在创建webcontext get之前在应用启动时实例化ViewModels,这意味着我在我的viewmodel构造函数中做了很多工作是个坏主意。

那么,我应该在viewmodel中检索将获得数据绑定的数据吗?

2 个答案:

答案 0 :(得分:0)

这是我在使用mvvm-light时避免使用的方法。因此,首先创建WebContext。

在App.xaml中:

 <Application.ApplicationLifetimeObjects>
        <ct:WebContext>
            <ct:WebContext.Authentication>
                <as:FormsAuthentication DomainContextType="MyProj.Data.AuthenticationContext, MyProj.Client.Common, Version=1.0.0." />
            </ct:WebContext.Authentication>
        </ct:WebContext>
    </Application.ApplicationLifetimeObjects>
    <Application.Resources>
        <ResourceDictionary>

            <ct:ViewModelLocator x:Key="Locator"
                                 d:IsDataSource="True" />
            <ResourceDictionary.MergedDictionaries>
                <ResourceDictionary Source="Assets/Styles.xaml" />
            </ResourceDictionary.MergedDictionaries>
        </ResourceDictionary>
    </Application.Resources>

答案 1 :(得分:0)

在App构造函数中实例化您的WebContext。然后在调用

之前将其添加到App_startup中的资源中
public App()
        {
            Startup += Application_Startup;
            Exit += Application_Exit;
            UnhandledException += Application_UnhandledException;

            if (IsInDesignModeStatic)
            {
                Services.ServiceLoader.LoadDesignTimeServices();
                DispatcherHelper.Initialize();
            }
            else
            {
                try
                {

                    ServiceLoader.LoadRunTimeServices();
                    DispatcherHelper.Initialize();

                    WebContext webContext = new WebContext();
                    ApplicationLifetimeObjects.Add(WebContext.Current);

                    FormsAuthentication fa = new FormsAuthentication();
                    fa.DomainContext = new Web.Services.AuthenticationDomainContext();
                    WebContext.Current.Authentication = fa;
                }
                catch (Exception ex)
                {
                    MessageBox.Show(ex.ToString());
                }
            }

            InitializeComponent();
        }



private void Application_Startup(object sender, StartupEventArgs e)
        {
            this.Resources.Add("WebContext", WebContext.Current);

            RootVisual = new MainPage();

        }

由于我的自定义AuthenticationDomainContext和Membershipprovider,我发现更容易在后面的代码中执行此部分...但Dereks也运行良好,我只是使用了代码,而我正在使一切正常工作。