Question

用户

Id  UserId   Date     Amount    NewBalance   NewTotal
---------------------------------------------------------
1   1      2020/03/21   100        100         100
2   1      2020/04/06   100        200         200
3   1      2020/04/07   25         225         225
4   2      2020/03/03   100        100         100
5   2      2020/04/07   30         130         130
6   3      2020/04/06   250        250        250

交易

newBalance

newTotal是该日期之前所有金额的总和，UserId UserName Amount_made_this_week --------------------------------------------- 1 3 Jon snow 250 2 1 Robert Baratheon 125 3 2 Cercei Lanister 30是该日期之前所有阳性金额的总和。

我想订购本周赚钱最多的人

所需结果：

{{1}}

如何用SQL编写？

Answer 1

您可以总结本周的amount过滤条件并排序结果：

SELECT Transactions.UserId, Users.Name, Sum(Transactions.Amount) as amount_made_this_week
FROM Transactions
    INNER JOIN Users
        ON Transactions.UserID = Users.ID
WHERE Transactions.Date BETWEEN #04/05/2020# AND #04/11/2020#
GROUP BY Userid, Name
ORDER BY amount_made_this_week DESC;

Answer 2

您还可以将日期范围与绑定变量无关，始终设置一个星期的时间，例如：

SELECT T.UserId, U.Name, Sum(T.Amount) as Amount_made_this_week
FROM Transactions T
    INNER JOIN Users U
       ON T.UserID = U.ID 
WHERE T.Date > (SYSDATE-7)
GROUP BY Userid, Name
ORDER BY Amount_made_this_week DESC;

如何计算SQL中多行之间的差异

2 个答案: