在我的并行编程书中,我遇到了这个代码,它说奴隶生成了数据集,但是,我认为master实际上生成了数据集。
这一行特别是我相信master生成数据集的原因。
for (i=0; i < ARRAY_SIZE; i++)
numbers[i] = i;
有人可以确认主设备或从设备是否生成数据集吗?
#include "mpi.h"
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#define TRIALS 20
#define ARRAY_SIZE 1000000
int main(int argc, char *argv[])
{
int myid, numprocs;
double startwtime, endwtime;
int namelen;
int* numbers = new int[ARRAY_SIZE];
int i, j, sum, part_sum;
int s, s0, startIndex, endIndex;
double totalTime;
char processor_name[MPI_MAX_PROCESSOR_NAME];
MPI_Init(&argc,&argv);
MPI_Comm_size(MPI_COMM_WORLD,&numprocs);
MPI_Comm_rank(MPI_COMM_WORLD,&myid);
MPI_Get_processor_name(processor_name,&namelen);
fprintf(stderr,"Process %d on %s\n", myid, processor_name);
fflush(stderr);
for (i=0; i < ARRAY_SIZE; i++)
numbers[i] = i;
if (myid == 0)
{
s = (int) floor(ARRAY_SIZE/numprocs);
s0 = s + ARRAY_SIZE%numprocs;
//printf("s=%d , s0= %d\n", s, s0);
}
MPI_Bcast(&s, 1, MPI_INT, 0, MPI_COMM_WORLD);
MPI_Bcast(&s0, 1, MPI_INT, 0, MPI_COMM_WORLD);
startIndex = s0 + (myid - 1)*s;
endIndex = startIndex + s;
totalTime = 0;
for (j = 1; j <= TRIALS; j++)
{
if (myid == 0)
{
startwtime = MPI_Wtime();
}
sum = 0;
part_sum = 0;
if (myid == 0) // master
{
// compute sum of master's numbers
for (i = 0; i < s0; i++)
{
part_sum += numbers[i];
}
}
else
{
for (i = startIndex; i < endIndex; i++)
{
part_sum += numbers[i];
}
}
MPI_Reduce(&part_sum, &sum, 1, MPI_INT, MPI_SUM, 0, MPI_COMM_WORLD);
if (myid == 0)
{
double runTime;
endwtime = MPI_Wtime();
runTime = endwtime - startwtime;
printf("Trial %d : Execution time (sec) = %f\n", j, runTime);
printf("Sum = %d \n", sum);
totalTime += runTime;
}
} // end for
if (myid == 0)
printf("Average time for %d trials = %f", TRIALS, totalTime/TRIALS);
MPI_Finalize();
}
答案 0 :(得分:2)
主服务器和都会生成整个数组。您必须记住,您的程序在所有节点上运行,并且有问题的代码部分不区分主/从。所以你的书的措辞没有错,但可以澄清。 :)