Question

我正在尝试构建一个电报机器人来为我的儿子玩游戏。基本上，我想通过使用命令处理程序从bot获得响应。当我请求命令处理程序时，应该从2个不同的列表中随机给出响应。

游戏正在预测食物名称，例如“苹果派”，苹果将在列表1中，而馅饼将在列表2中并且该机器人应从列表中获取不同的值，并通过命令处理程序以一条消息的形式给出响应。

将感谢您的指导/帮助

下面是python代码：



from telegram.ext import Updater, CommandHandler, MessageHandler, Filters
from telegram import error, update
import sys
import os
import random

import logging
logging.basicConfig(level=logging.DEBUG,
                    format='%(asctime)s - %(name)s - %(levelname)s - %(message)s')

def start(update, context):
    """Send a message when the command /start is issued."""
    update.message.reply_text('Hello, play games!')


def shuffle2d(arr2d, rand_list=random):
    """Shuffes entries of 2-d array arr2d, preserving shape."""
    reshape = []
    data = []
    iend = 0
    for row in arr2d:
        data.extend(row)
        istart, iend = iend, iend+len(row)
        reshape.append((istart, iend))
        rand_list.shuffle(data)
    return [data[istart:iend] for (istart,iend) in reshape]

def show(arr2d):
    """Shows rows of matrix (of strings) as space-separated rows."""
    show ("\n".join(" ".join(row) for row in arr2d))
    A = A.rand_list['APPLE, PUMKIN, STRAWBERRY, BANANA,CHOCOLATE']
    B = B.rand_list['PIE, ICE-CREAM, CAKE,SHAKE'] 
    arr2d = []
    arr2d.append([A+(j) for j in range(1,B+1)])
    show(shuffle2d(arr2d))
    print(show)
    return show

def play(update, context):
    """Send a message when the command /play is issued."""
    update.message.reply_text(shuffle2d)

def main():
    """Start the bot."""
    # Create the Updater and pass it your bot's token.
    # Make sure to set use_context=True to use the new context based callbacks
    # Post version 12 this will no longer be necessary
    updater = Updater("1XXXXXXX:XXXXXXXXXXXXXXXXXXY", use_context=True)


    # Get the dispatcher to register handlers
    dp = updater.dispatcher

    # on different commands - answer in Telegram
    dp.add_handler(CommandHandler("start", start))
    dp.add_handler(CommandHandler("play", play))


    # on noncommand i.e message - echo the message on Telegram
    dp.add_handler(MessageHandler(Filters.text, play))


    # Start the Bot
    updater.start_polling()

    # Run the bot until you press Ctrl-C or the process receives SIGINT,
    # SIGTERM or SIGABRT. This should be used most of the time, since
    # start_polling() is non-blocking and will stop the bot gracefully.
    updater.idle()


if __name__ == '__main__':
    main()

Answer 1

在此代码中，您使用名为shuffleDish()的函数来创建一个字符串，该字符串包含从分开的列表中选择的两个随机单词，并从命令处理程序“播放”中调用它

from telegram.ext import Updater, CommandHandler
from telegram import error, update
import random
import logging

logging.basicConfig(level=logging.INFO,
                format='%(asctime)s - %(name)s - %(levelname)s - %(message)s')
logger = logging.getLogger(__name__)

def shuffleDish():
    A = ['APPLE', 'PUMKIN', 'STRAWBERRY', 'BANANA', 'CHOCOLATE']
    B = ['PIE', 'ICE-CREAM', 'CAKE', 'SHAKE']
    dish = random.choice(A)+" "+random.choice(B)
    return dish

def play(update, context):
    update.message.reply_text(shuffleDish())

def error(update, context):
    logger.warning('Update "%s" caused error "%s"', update, context.error)

def main():
    updater = Updater(tgtoken, use_context=True)
    dp = updater.dispatcher
    dp.add_handler(CommandHandler("play", play))
    dp.add_error_handler(error)
    updater.start_polling()
    updater.idle()

if __name__ == '__main__':
    main()

电报游戏机器人

1 个答案: