Question

我正在通过游戏实现我的机器人电报。我写了这个：

$content = file_get_contents("php://input");
$update = json_decode($content, true);
if(!$update)
{
    exit;
}
$chatId = isset($message['chat']['id']) ? $message['chat']['id'] : "";

header("Content-Type: application/json");
$parameters = array('chat_id' => $chatId);
$parameters["method"] = "sendGame";
$parameters["game_short_name"] = "prova";
$parameters["text"] = parse_url("<my_html_5_url>");
$message = json_encode($parameters);
echo json_encode($parameters);

我的示例html5代码是：

<!DOCTYPE html>
<html>
    <head>
        <meta charset="UTF-8">
        <title>Title of the document</title>
    </head>

    <body>
        Content of the document......
    </body>

</html>

当我打电话给游戏时，我只看到Botfather插入的图像，但我没有机会看到我的html5。我哪里错了？

Answer 1

我以这种方式编辑：

$content = file_get_contents("php://input");
$update = json_decode($content, true);

if(!$update)
{
  exit;
}

$message = isset($update['message']) ? $update['message'] : "";
$messageId = isset($message['message_id']) ? $message['message_id'] : "";
$chatId = isset($message['chat']['id']) ? $message['chat']['id'] : "";
header("Content-Type: application/json");

if(isset($update["callback_query"])) {
  $parameters["method"] = "answerCallbackQuery";
  $parameters["callback_query_id"] = $update["callback_query"]["id"];
  $parameters["url"] = "<my_html_5_url>";
  echo json_encode($parameters);

  die;
}
$parameters = array('chat_id' => $chatId);
$parameters["method"] = "sendGame";
$parameters["game_short_name"] = "prova";

echo json_encode($parameters);

电报机器人游戏无法正常工作

1 个答案: