Question

如何使用php从数据库获取数据并显示它？

数据库表中有列，标记为ID＆amp; Number。 ID是独一无二的。固定而数字只是一个非唯一的数字。如果有人访问 http://example.com/show.php?ID=32和show.php应该抓取Number＆amp;显示"Your number is XXX”

请提供代码示例。

Answer 1

首先获取用户的ID（可以在访问时或根据访问时提供的详细信息给出）

然后将select查询写入包含'number'field.like

的表

SELECT number FROM table1 WHERE table1.ID=IDFromtheuser;

Answer 2

<?php
//Connect to DB
$db = mysql_connect("localhst","user","pass") or die("Database Error");
mysql_select_db("db_name",$db);

//Get ID from request
$id = isset($_GET['id']) ? (int)$_GET['id'] : 0;

//Check id is valid
if($id > 0)
{
    //Query the DB
    $resource = mysql_query("SELECT * FROM table WHERE id = " . $id);
    if($resource === false)
    {
        die("Database Error");
    }

    if(mysql_num_rows($resource) == 0)
    {
        die("No User Exists");
    }

    $user = mysql_fetch_assoc($resource);

    echo "Hello User, your number is" . $user['number'];
}

这是非常基本的，但应该会看到你。

Answer 3

试

SELECT number from numberTable nt
JOIN idTable it ON  it.ID = nt.ID
WHERE it.ID = `your given id`

因为我认为你的两个表都是用id

引用的

Answer 4

<?php
$host="localhost"; 
$username=""; 
$password=""; 
$db_name="multiple_del"; 
$tbl_name="test_mysql"; 

// Connect to server and select databse.
mysql_connect("$host", "root", "")or die("cannot connect");
mysql_select_db("multiple_del")or die("cannot select DB");

$sql="SELECT * FROM test_mysql";


$result=mysql_query($sql);

$count=mysql_num_rows($result);

?>

<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="form1" method="post" action="">
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td bgcolor="#FFFFFF">&nbsp;</td>
<td colspan="4" bgcolor="#FFFFFF"><strong>Delete multiple rows in mysql</strong> </td>
</tr>
<tr>
<td align="center" bgcolor="#FFFFFF">#</td>
<td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Name</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Lastname</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td>
</tr>

<?php
while($rows=mysql_fetch_array($result)){
?>

<tr>
<td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td>
<td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['name']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['lastname']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td>
</tr>

<?php
}
?>

<tr>
<td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td>
</tr>

<?php


if($delete){
for($i=0;$i<$count;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM test_mysql WHERE id='$del_id'";
$result = mysql_query($sql);
}


}

?>

</table>
</form>
</td>
</tr>
</table>



its my code but its not working and error are show in this code:-

<?php


if($delete){
for($i=0;$i<$count;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM test_mysql WHERE id='$del_id'";
$result = mysql_query($sql);
}


}

?>

please help me.

如何从数据库中获取数据并在PHP中显示？

4 个答案: