Question

我正在使用以下代码从数据库中获取数据。当我插入所有列值时，它显示我的输出正确。例如，我为＆＃39; Hip＆＃39;插入NULL值。所以它没有以表格形式显示。

请提前帮助我，谢谢！

$sizeArray         = explode(',', $rows['sizes']);
$bustArray         = explode(',', $rows['bust']);
$hipArray          = explode(',', $rows['hip']);
$lengthArray       = explode(',', $rows['length']);
$lengthArraybottom = explode(',', $rows['lengthbottom']);
$shoulderArray     = explode(',', $rows['shoulder']);

foreach ($sizeArray as $key => $value) {
    foreach ($bustArray as $bkey => $bvalue) {
        foreach ($waistArray as $Wkey => $Wvalue) {
            foreach ($hipArray as $hkey => $hvalue) {
                foreach ($lengthArray as $lkey => $lvalue) {
                    foreach ($lengthArraybottom as $lkeybottom => $lbottomvalue) {
                        foreach ($shoulderArray as $skey => $svalue) {
                            if ($key == $bkey && $bkey == $Wkey && $Wkey == $hkey && $hkey == $lkey && $lkey == $lkeybottom && $lkeybottom == $skey) {

                                echo '<tr><td>' . $value . '</td>';
                                echo '<td>' . $bvalue . '</td>';
                                echo '<td>' . Wvalue . '</td>';
                                echo '<td>' . $hvalue . '</td>';
                                echo '<td>' . $lvalue . '</td>';
                                echo '<td>' . $lbottomvalue . '</td>';
                                echo '<td>' . $svalue . '</td></tr>';

                            }
                        }
                    }
                }
            }
        }
    }
}

Answer 1

<table class="data-table">
    <caption class="title">Sales Data of Electronic Division</caption>
    <thead>
        <tr>
            <th>NO</th>
            <th>CUSTOMER</th>
            <th>ITEM</th>
            <th>DATE</th>
            <th>AMOUNT</th>
        </tr>
    </thead>
    <tbody>
    <?php
    $no     = 1;
    $total  = 0;
    while ($row = mysqli_fetch_array($query))
    {
        $amount  = $row['amount'] == 0 ? '' : number_format($row['amount']);
        echo '<tr>
                <td>'.$no.'</td>
                <td>'.$row['name'].'</td>
                <td>'.$row['item'].'</td>
                <td>'. date('F d, Y', strtotime($row['date'])) . '</td>
                <td>'.$amount.'</td>
            </tr>';
        $total += $row['amount'];
        $no++;
    }?>
    </tbody>
    <tfoot>
        <tr>
            <th colspan="4">TOTAL</th>
            <th><?=number_format($total)?></th>
        </tr>
    </tfoot>
</table>

参考：http://webdevzoom.com/display-mysql-data-html-5-table-using-php/

如何从数据库中获取数据并以表格格式显示？

1 个答案: