我有一个带键值对的标准数组 - 我想用键将它转换成一个多维数组。困难似乎是我需要递归循环未知数量的新密钥并将它们转换为多维数组。简而言之,我想要这个:
$val[alfa.xray.uno] = "Some value";
=> $val['alfa']['xray']['uno'] = "Some value";
实施例: (代码失败,还需要处理N维 - 但你明白了。)
$arr['alfa.xray.uno'] = "Alfa X-Ray Uno";
$arr['alfa.yaho.duo'] = "Alfa Yaho Duo";
$arr['beta.xray.uno'] = "Beta X-Ray Uno";
$arr['beta.xray.duo'] = "Beta X-Ray Duo";
$arr['just-me'] = "Root-level item";
print_r( array_flat_to_multidimensional($arr) );
function array_flat_to_multidimensional($arr) {
foreach($arr as $key=>$val) {
$key = explode(".",$key);
for($i=0; $i<count($key); $i++) {
if($i==0) { $out[$key[$i]] = $val; }
else if($i==1) { $out[$key[$i-1]][$key[$i]] = $val; }
else if($i==2) { $out[$key[$i-2]][$key[$i-1]][$key[$i]] = $val; }
else if($i==3) { $out[$key[$i-3]][$key[$i-2]][$key[$i-1]][$key[$i]] = $val; }
}
}
return $out;
}
也许RecursiveArrayIterator可以解决这个问题?
答案 0 :(得分:7)
您可以使用引用连续迭代并构建嵌套数组结构:
$out = array();
foreach ($arr as $key=>$val) {
$r = & $out;
foreach (explode(".", $key) as $key) {
if (!isset($r[$key])) {
$r[$key] = array();
}
$r = & $r[$key];
}
$r = $val;
}
return $out;
答案 1 :(得分:2)
使用递归Luke
function ins(&$ary, $keys, $val) {
$keys ?
ins($ary[array_shift($keys)], $keys, $val) :
$ary = $val;
}
// test
$arr['alfa.xray.uno'] = "Alfa X-Ray Uno";
$arr['alfa.yaho.duo'] = "Alfa Yaho Duo";
$arr['beta.xray.uno'] = "Beta X-Ray Uno";
$arr['beta.xray.duo'] = "Beta X-Ray Duo";
$arr['just-me'] = "Root-level item";
$a = array();
foreach($arr as $k => $v)
ins($a, explode('.', $k), $v);
print_r($a);
答案 2 :(得分:1)
您可以在遍历数组层次结构级别时使用reference: