Question

我正在使用ms sql研究分层数据（作为概括工单的解决方案）。

*

我愿意在我的初始表上设计更改和/或添加其他内容表。

*

这是我的数据

ID  ParentID    Type        Value
38  0           Num         327
39  38          Sector      21
40  38          Sector      22
43  40          Product     NS
44  40          Product     MS
50  40          Temp        RAS
48  44          Quantity    60
47  43          Quantity    25
41  39          Product     ARF
42  39          Product     BRF
49  39          Temp        RAS
51  39          Cible       Acarien A.
46  42          Quantity    30
52  42          Cible       Acarien B.
45  41          Quantity    20

我想将其转换为：

Num Sector  Product Quantity
327 21      ARF     20
327 21      BRF     30
327 22      NS      25
327 22      MS      60

[使用Gurwinder的结果]

num sector  product    quantity
327 22      MS         60
327 22      NS         25
327 21      BRF        30
327 21      BRF        Acarien B.
327 21      ARF        20

[Shungo＆＃39;方法]

<root>
  <row Num="327" Sector="s2" Temp="normal" />
  <row Num="327" Sector="s2" Product="BRF" Qte="70" />
  <row Num="327" Sector="s2" Product="ARF" Qte="45" />
  <row Num="327" Sector="s1" Temp="normal" />
  <row Num="327" Sector="s1" Cible="Acarien a." />
  <row Num="327" Sector="s1" Product="NS" Qte="35" />
  <row Num="327" Sector="s1" Product="NS" Cible="Acarien b." />
  <row Num="327" Sector="s1" Product="MS" Qte="60" />
</root>

感谢您的时间。

Answer 1

这个技巧怎么样？

DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(10),Value VARCHAR(10))
INSERT INTO @tbl VALUES
 (1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60');

WITH recCTE AS
(
    SELECT *,0 AS HLevel,Type + N'="' + CAST(Value AS NVARCHAR(MAX)) + N'" ' AS attr
    FROM @tbl WHERE ParentID=0

    UNION ALL

    SELECT t.*,r.HLevel+1,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
    FROM @tbl AS t
    INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr  + N'/>' AS XML)
FROM recCTE
WHERE HLevel=3
FOR XML PATH(''),ROOT('root')

结果

<root>
  <row Num="327" Sector="22" Product="MS" Quantity="60" />
  <row Num="327" Sector="22" Product="NS" Quantity="25" />
  <row Num="327" Sector="21" Product="BRF" Quantity="30" />
  <row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>

此XML易于查询... 最深层次（此处我使用HLevel = 3）可以一般找到 - 但您需要提供更多详细信息...... < / p>

更新

以下不会将给定深度用作过滤器，而是使用查询来检查节点是否为叶节点

我在最后添加了一行

DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
 (1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60')
,(13,11,'SomeMore','Test as fourth');

WITH recCTE AS
(
    SELECT t.*
          ,0 AS HLevel
          ,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
          ,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
    FROM @tbl AS t WHERE ParentID=0

    UNION ALL

    SELECT t.*
          ,r.HLevel+1
          ,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
          ,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
    FROM @tbl AS t
    INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr  + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')

结果

<root>
  <row Num="327" Sector="22" Product="MS" Quantity="60" SomeMore="Test as fourth" />
  <row Num="327" Sector="22" Product="NS" Quantity="25" />
  <row Num="327" Sector="21" Product="BRF" Quantity="30" />
  <row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>

更新2：使用真实数据

正如您发现的那样，您的问题非常混乱......不知道您真正需要什么，但如果我通过此查询运行您的真实数据我就会得到这个：

DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
 (38,0,'Num','327')
,(39,38,'Sector','21')
,(40,38,'Sector','22')
,(43,40,'Product','NS')
,(44,40,'Product','MS')
,(50,40,'Temp','RAS')
,(48,44,'Quantity','60')
,(47,43,'Quantity','25')
,(41,39,'Product','ARF')
,(42,39,'Product','BRF')
,(49,39,'Temp','RAS')
,(51,39,'Cible','Acarien A.')
,(46,42,'Quantity','30')
,(52,42,'Cible','Acarien B.')
,(45,41,'Quantity','20');

WITH recCTE AS
(
    SELECT t.*
          ,0 AS HLevel
          ,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
          ,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
    FROM @tbl AS t WHERE ParentID=0

    UNION ALL

    SELECT t.*
          ,r.HLevel+1
          ,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
          ,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
    FROM @tbl AS t
    INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr  + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')

结果

<root>
  <row Num="327" Sector="22" Temp="RAS" />
  <row Num="327" Sector="22" Product="MS" Quantity="60" />
  <row Num="327" Sector="22" Product="NS" Quantity="25" />
  <row Num="327" Sector="21" Temp="RAS" />
  <row Num="327" Sector="21" Cible="Acarien A." />
  <row Num="327" Sector="21" Product="BRF" Quantity="30" />
  <row Num="327" Sector="21" Product="BRF" Cible="Acarien B." />
  <row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>

Answer 2

select t1.value num,
    t2.value sector,
    t3.value product,
    t4.value quantity
from table t1
inner join table t2
on t1.id = t2.parentid
and t1.parentid = 0
inner join table t3
on t2.id = t3.parentid
inner join table t4
on t3.id = t4.parentid;

将分层数据转换为平面表

2 个答案:

更新

更新2：使用真实数据