分割字符串并获取最后一个项目

Question

directory <- "/home/rstudio-doug/analysis/radhoc/revenue_model/models/fungame/trained_to_202001"

我想获取“ trained_to_202001”作为变量。尝试过：

directory %>% str_split("/") %>% last()
[1] ""                  "home"              "rstudio-doug"     "analysis"          "radhoc"            "revenue_model"    
[7] "models"            "fungame"      "trained_to_202001"

然后尝试： 目录％>％str_split（“ /”）％>％tail（n = 1）

[[1]]
[1] ""                  "home"              "rstudio-doug"     "analysis"          "radhoc"            "revenue_model"    
[7] "models"            "fungame"      "trained_to_202001"

如何获取“ trained_to_202001”？

Answer 1

如果您的最后一部分没有/（我认为是这样），则可以选择：

gsub('.*\\/', '', directory)

# [1] "trained_to_202001"

Answer 2

我们可以使用basename

basename(directory)
#[1] "trained_to_202001"

Answer 3

尝试使用unlist之前先使用last，如下所示

directory %>% str_split("/") %>% unlist %>% last()

[1] "trained_to_202001"