我有一个问题!我希望函数 getMealSummary ()在 for循环完成后返回(我不包括返回键,因为该函数很大,我只是有疑问在本节中。)
我该如何使用异步/等待或诺言?
谢谢
export const getMealMicroSummaryHelper = async function getMealSummary(array, populatedFoods, customMeasurements, isRecipe,expertId){
var [totalZinc, totalCalcium,totalAlphaCarotene,totalBetaCarotene,totalCholine,totalCopper,totalBetaCrypto,totalFluoride,totalVitaminB9,totalIron,
totalLutein,totalLycopene,totalMagnesium,totalManganese,totalNiacin,totalVitaminB5,totalPhosphorus,totalPotassium,totalRetinol,totalRiboflavin,
totalSelenium,totalSodium,totalTheobromine,totalVitaminA,totalVitaminB12,totalVitaminB6,totalVitaminC,totalVitaminD,totalVitaminD2,totalVitaminD3,
totalVitaminE,totalThiamin] = [0, 0, 0, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
let recipesArray = []
for(let i = 0; i < populatedFoods.length; i++){
if(populatedFoods[i].foodType === 4){
await apiCall("get",`/api/experts/${expertId}/recipes/${populatedFoods[i]._id}`)
.then(recipe =>{
recipesArray.push(recipe)
})
.catch((err)=>console.log(err))
}
答案 0 :(得分:1)
您可以使用map()
和Promise.all
的组合,例如:
async function getMealSummary(array, populatedFoods, customMeasurements, isRecipe, expertId) {
try {
let recipesArray = await Promise.all(
populatedFoods.map(async populatedFoods => {
if (populatedFoods[i].foodType === 4) {
let recipe = await apiCall("get", `/api/experts/${expertId}/recipes/${populatedFoods[i]._id}`)
return recipe;
}
})
)
} catch (err) {
console.log(err)
}
}
这只是一个简单的版本,可为您提供基本的想法。我没有包括您在recipesArray
以上声明的所有变量。这些将需要根据需要包括在内。