Question

基本上我想要实现的是在类deltaKinematics中创建类geneticAlgorithm的本地（和私有）实例

在我的geneticAlgorithm.h文件中：

class DeltaKinematics; //class is defined in separate linked files

class GeneticAlgorithm {
  //private  
    DeltaKinematics deltaRobot;

public:

    GeneticAlgorithm(); //constructor

};

这很好，但是当我去声明GeneticAlgorithm构造函数时，我无法弄清楚如何构造DeltaKinematics的实例

这是geneticAlgorithm.cpp构造函数：

GeneticAlgorithm::GeneticAlgorithm(){ //The error given on this line is "constructor for 'GeneticAlgorithm' must explicitly initialize the member 'deltaRobot' which does not have a default constructor"

    DeltaKinematics deltaRobot(100); //this clearly isn't doing the trick

    cout << "Genetic Algorithmic search class initiated \n";
}

如何初始化该本地实例？

Answer 1

会员初始化人名单：

GeneticAlgorithm::GeneticAlgorithm() : deltaRobot(100) {
}

Answer 2

GeneticAlgorithm::GeneticAlgorithm() : deltaRobot(100) {
    cout << "Genetic Algorithmic search class initiated \n";
}

注意构造函数名后面的:：它是类的成员数据变量的初始化序列的开始。它们显示为对其构造函数的调用，具有您想要传递的参数，并且应该与它们声明的顺序相同。

C ++ - 如何从类的构造函数初始化单独类的构造函数？

2 个答案: