Question

我最初的解决方案来自this对类似问题的评论。但是，如果我这样做并实施进入我的代码的不同部分，它将不再计算游戏中的CASH计数器。

CASH = 0
DPS = 5
HPofMonster = 10
starttime=time.time()

def handle_monster():
    global HPofMonster, CASH
    if pygame.mouse.get_focused():
        event = pygame.event.poll()
        mouse_x, mouse_y = pygame.mouse.get_pos()
        if GEN1.collidepoint(mouse_x, mouse_y) and event.type == MOUSEBUTTONDOWN and event.button == 1:
            HPofMonster -= 1
            print('click')
            pass
        else:
            print('Not Pushed OR not on Monster')
            pass
    else:
        print('Mouse not focused')
        pass
    if HPofMonster < 0:
        CASH += 5
        HPofMonster = 10
        print('reset')

def handle_dps():
    global HPofMonster
    HPofMonster -= DPS
    print("tick")
    time.sleep(1.0 - ((time.time() - starttime) % 1.0))


def game_loop():
    while True:
        handle_dps()
        handle_monster()
        update_text()
        handle_events()



def main():
    pygame.display.set_caption('Clicker')
    game_loop()


main()

当我不移动鼠标时，控制台如下所示：

刻度

未在怪物上按下或未按下

刻度

未按入或未按怪物

刻度

未在怪物上按下或未按下

重置

刻度

未在怪物上按下或未按下

刻度

未按入或未按怪物

刻度

未在怪物上按下或未按下

重置

刻度

未在怪物上按下或未按下

刻度

未在怪物上按下或未按下

刻度

未在怪物上按下或未按下

重置

鼠标未聚焦

进程已完成，退出代码为0

这是完整的代码：

import pygame, threading, time

from threading import Event, Thread
from pygame.locals import *


pygame.init()

WIDTH = 800
HEIGHT = 600
WINDOW = pygame.display.set_mode((WIDTH, HEIGHT))
CASH = 0
DPS = 5
HPofMonster = 10
BACKGROUND_COLOR = (0, 0, 0)
BUTTON_COLOR = (0, 255, 0)
starttime=time.time()

FONT = pygame.font.SysFont('monospace', 15)

# Main Screen for drawing buttons
DRAW_SCREEN = pygame.Surface((WIDTH, HEIGHT))
DRAW_SCREEN.fill(BACKGROUND_COLOR)

# Buttons
GEN1 = pygame.draw.rect(DRAW_SCREEN, BUTTON_COLOR, pygame.Rect(200, 200, 200, 200), 1)
GEN1_LABEL = FONT.render('Defeat the Monster', 1, (255, 255, 0))


def handle_monster():
    global HPofMonster, CASH
    if pygame.mouse.get_focused():
        event = pygame.event.poll()
        mouse_x, mouse_y = pygame.mouse.get_pos()
        if GEN1.collidepoint(mouse_x, mouse_y) and event.type == MOUSEBUTTONDOWN and event.button == 1:
            HPofMonster -= 1
            print('click')
            pass
        else:
            print('Not Pushed OR not on Monster')
            pass
    else:
        print('Mouse not focused')
        pass
    if HPofMonster < 0:
        CASH += 5
        HPofMonster = 10
        print('reset')


def handle_events():
    event_dict = {
        pygame.QUIT: exit,
    }
    for event in pygame.event.get():
        if event.type in event_dict:
            event_dict[event.type]()


def update_text():
    global CASH_LABEL, DPS_LABEL, GEN1_LABEL, DPS, CASH
    WINDOW.blit(DRAW_SCREEN, (0, 0))
    WINDOW.blit(GEN1_LABEL, (10, 108))
    CASH_LABEL = FONT.render('Total Cash: ${}'.format(CASH), 1, (255, 255, 0))
    DPS_LABEL = FONT.render('Total DPS: ${}'.format(DPS), 1, (255, 65, 0))
    WINDOW.blit(CASH_LABEL, (0, 0))
    WINDOW.blit(DPS_LABEL, (0, 20))
    pygame.display.flip()


def handle_dps():
    global HPofMonster
    HPofMonster -= DPS
    print("tick")


def game_loop():
    while True:
        handle_dps()
        handle_monster()
        update_text()
        handle_events()



def main():
    pygame.display.set_caption('Clicker')
    game_loop()


main()

Answer 1

请勿在事件驱动程序中使用time.sleep()。它阻止了事件循环，并且在某些系统上，窗口管理器或外围操作系统会认为程序已停止和/或崩溃。该程序必须不断处理传入的事件。

在pygame中执行此操作的一种简单方法是使用实时系统时钟函数pygame.time.get_ticks()，该函数返回自程序启动以来的毫秒数，并且它会不断增加。如果您希望将来触发某些事件，请设置一个时间戳，例如：

future_timestamp = pygame.time.get_ticks() + 15000   # 15 seconds from now

...

# somewhere else in the code, maybe in the main loop
time_now = pygame.time.get_ticks()
if ( future_timestamp < time_now ):
    # do the thing that had to happen
    do_that_thing()
    # re-set the timer for next time
    future_timestamp = time_now + 15000

另一种实现定期发生的事情的简单方法是设置pygame计时器：

pygame.time.set_timer( pygame.USEREVENT + 1, 3500 )   # Cash every 3500 milliseconds

# Main Loop 
while not exiting:
    # Handle user-input
    for event in pygame.event.get():
        if ( event.type == pygame.QUIT ):
           done = True
        elif ( event.type == pygame.USEREVENT + 1 ):
           CASH += 1   
           # reset the event-timer
           pygame.time.set_timer( pygame.USEREVENT + 1, 3500 )

Answer 2

使用time.sleep或pygame.time.delay()代替pygame.time.wait()。

以下是官方pygame时间事件的链接：https://www.pygame.org/docs/ref/time.html

有没有一种方法可以每x秒运行一次函数？（DPS）

2 个答案:

有没有一种方法可以每x秒运行一次函数？ （DPS）

2 个答案:

有没有一种方法可以每x秒运行一次函数？（DPS）