我有下表。
CUST_ID START_CYCLE END_CYCLE WORKER CUST_SUB_ID CUST_SUB_TYPE
101 1/1/2019 1/31/2019 ABC123 134 HIGH_SUB
101 2/1/2019 4/30/2019 ABC123 136 HIGH_SUB
101 5/1/2019 7/31/2019 ABC123 1414 HIGH_SUB
101 8/1/2019 8/30/2019 ABC123 1469 HIGH_SUB
发生以下情况时,我需要合并日期(不包括行)。
条件:
lead
cust_sub_id <>
cust_sub_id
lead
cust_sub_type = cust_sub_type
lead
cust_id = cust_id
lead
工人=工人
最终输出:
CUST_ID START_CYCLE END_CYCLE WORKER CUST_SUB_ID CUST_SUB_TYPE
101 1/1/2019 8/30/2019 ABC123 134:136:1414:1469 HIGH_SUB
SQL:
select
cust_id,
start_cycle,
end_cycle,
worker,
cust_sub_id,
cust_sub_type,
gaps_in_srv,
case
when gaps_in_srv = 'N'
and cust_sub_id <> lead(cust_sub_id) over (partition by cust_id order by start_cycle)
and cust_id = lead(cust_id) over (partition by cust_id order by start_cycle)
and worker = lead(worker) over (partition by cust_id order by start_cycle)
then 'Y'
else 'N'
end merge_dts,
dense_rank() over (partition by cust_id, cust_sub_id order by start_cycle) rnk_fst_dt,
dense_rank() over (partition by cust_id, cust_sub_id order by start_cycle desc) rnk_lst_dt
from cust_cycle
删除行后,我可以使用listagg
来捕获cust_sub_id,但是在应用listagg函数之前,需要帮助删除这些行。
答案 0 :(得分:1)
您可以使用def takeShot():
root.withdraw()
sc = ImageGrab.grab()
root.deiconify()
path = filedialog.asksaveasfilename(defaultextension='.png')
sc.save(path)
来确定“岛屿”的起点,并通过累积总和为该岛分配分组编号来解决此问题:
lag()