解决约束问题需要帮助（第二）

Question

我已经解决了以下约束处理任务。你可以验证它是否正确吗？

One of the prisoners of a high-level security prison sees a way to escape. Almost
free, he reaches a corridor of 20 meters long, guarded by 5 cameras, behind
which is the exit. In Figure 3, we provide a schematic overview of the corridor.

The prisoner has only 10 seconds to reach the end of the corridor and may 
not be noticed by the cameras in doing so. After 10 seconds, or when seen by a
camera, the prison is put under total lock-down, which will prevent his escape.
We will consider the following constraints:

• A camera can only see 3 meters and cannot see its own position. E.g., the
camera at position 9 is able to see the positions 6, 7 and 8, or 10, 11 and
12, depending on the orientation of the camera.

• At time point 0, all cameras are oriented towards the end of the corridor.
Thus, the camera at position 9 sees positions 10, 11 and 12.

• Every two seconds the cameras change their orientation. Thus, at time
point 2 the camera at position 9 will see the positions 6, 7 and 8.

• Every second, the prisoner can move 0, 1, 2 or 3 meters forward. He
cannot move backward. Thus, if the prisoner is standing at position 2 at
time point 2, then, at time point 3, he can be on position 2, 3, 4 or 5.

Formulate the problem above as a constraint problem. Come up with a useful
representation of the problem in terms of the constraint processing tool. Provide
an explanation of indices, variables and domains. Furthermore, provide for every
introduced constraint, the meaning of the constraint in natural language.

这是我的解决方案，希望你们检查一下我做错了什么：

***MY VARIABLES***

Name: T, domain: 0..10                 // T = the time from 0 to 10 seconds  

Name: P, domain: 0..3                   // P = Prisoner can move 0, 1, 2, 3 meters

Name: C1, domain: 2                     // C1 = camera 1

Name: C2, domain: 4                     // C2 = camera 2

Name: C3, domain: 9                       // C3 = camera 3

Name: C4, domain: 12                      // C4 = camera 14

Name: C5, domain: 17                      // C5 = camera 5

Name: View1, domain: -1..5                // camera1 view

Name: View2, domain: 1..7                   // camera2 view

Name: View3, domain: 6..12                 // camera3 view

Name: View4, domain: 9..15                 // camera4 view

Name: View5, domain: 14..20                // camera5 view

MY CONSTRAINTS
我以这样一种方式宣布约束，即每当相机的视图发生变化时，时间是偶数，但是当时间是一次时，只有囚犯可以移动。

 Constraint: (T=0/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=1/\P(i)), range: i>0
    Constraint: (T=2/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
    Constraint: (T=3/\P(i)), range: i>0
    Constraint: (T=4/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=5/\P(i)), range: i>0
    Constraint: (T=6/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
    Constraint: (T=7/\P(i)), range: i>0
    Constraint: (T=8/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=9/\P(i)), range: i>0
    Constraint: (T=10/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1

伙计们，我知道我做错了所以请帮我纠正。

感谢您的帮助。我昨天发布了一个类似的问题，所以如果你想知道变量和约束的语法，那么这就是链接： Variable and Constraint syntax in this post

感谢您的帮助

Answer 1

你已经忘记了相机无法看到自己：“相机只能看到3米，看不到自己的位置”。因此，View1，View2 ...... View5应该被修改。

Als，你需要一个变量作为囚犯的位置（你只有一个囚犯的移动）

我正在寻找其他错误。