Question

我有以下一些数据，需要在同一行中获取星期数和年份。

data.head()

+---------------+
|     epoch     |
+---------------+
| 1580495399964 |
| 1580495399334 |
| 1580495397591 |
| 1580495396967 |
| 1580495396331 |
+---------------+

我如何获得这样的结果：

data.head()
+---------------+-----------+
|     epoch     | week-year |
+---------------+-----------+
| 1580495399964 | 4-2020    |
| 1580495399334 | 4-2020    |
| 1580495397591 | 4-2020    |
| 1580495396967 | 4-2020    |
| 1580495396331 | 4-2020    |
+---------------+-----------+

Answer 1

尝试：

data['week-year'] = data.epoch.apply(pd.to_datetime, unit='ms')
data['week-year'] = data['week-year'].dt.strftime('%U-%Y')

           epoch week-year
0  1580495399964    4-2020
1  1580495399334    4-2020
2  1580495397591    4-2020
3  1580495396967    4-2020
4  1580495396331    4-2020

Answer 2

下面的代码行，您可以用来生成所需格式的输出：

import time

time1 = 1580495399964
base = time.gmtime(1580495399964 / 1000)
print("{0:2}-{1:4}".format(base.tm_mon, base.tm_year))

Answer 3

data['week-year'] = pd.to_datetime(data['epoch']+19800, unit='ms').dt.strftime('%U-%Y')


+------------------+-----------+
|  epoch week-year | week-year |
+------------------+-----------+
| 0  1580495399964 | 4-2020    |
| 1  1580495399334 | 4-2020    |
| 2  1580495397591 | 4-2020    |
| 3  1580495396967 | 4-2020    |
| 4  1580495396331 | 4-2020    |
+------------------+-----------+

注意：如果您的时代仅在格林尼治标准时间加

，请添加19800

如何从纪元获取星期数和年份

3 个答案: