Question

如何获取一个星期中的星期一的日期以及一年中的年数？

例如，如果年份为2020，年份中的星期数为01，则预期结果为2019-12-30

Answer 1

希望这就是您想要的:)

<?php

$week_number = '06';
$year_number = '2020';

function getStartAndEndDate($week, $year) {
  $date = new DateTime();
  $date->setISODate($year, $week);
  for ($i=0; $i < 7; $i++) {
    $array[$i] = $date->format('Y-m-d');
    $date->modify('+1 days');
  }
  return $array;
}

$week_array = getStartAndEndDate($week_number,$year_number);

echo $week_array[0]; // 0 = monday, 1 = tuesday, and so on :)

?>

Answer 2

<?php
$week = 1;
$year = 2020;

$dateTime = date_create(sprintf("%04dW%02d",$year,$week)); //always a monday

echo $dateTime->format('Y-m-d');  //2019-12-30

获取具有年份的星期几和一年中的星期数

2 个答案: