我正在尝试获得列数和＆amp;行汇总与前一行总和和列总和。
例如。
我的初始数据框是：
Flag1 Flag2 Flag3 Type1 Type2 Type3
1 Level1 A FIRST 2 0 0
2 Level1 A SECOND 1 9 0
3 Level1 A THIRD 3 7 0
4 Level1 A FOURTH 9 18 0
5 Level1 A FIFTH 1 22 0
6 Level1 A SIXTH 1 13 0
7 Level1 B FIRST 0 0 0
8 Level1 B SECOND 3 9 0
9 Level1 B THIRD 5 85 0
10 Level1 B FOURTH 4 96 0
11 Level1 B FIFTH 3 40 0
12 Level1 B SIXTH 0 17 0
22 Level2 A FIRST 2 0 0
23 Level2 A SECOND 1 9 0
24 Level2 A THIRD 3 7 0
25 Level2 A FOURTH 9 18 0
26 Level2 A FIFTH 1 22 0
27 Level2 A SIXTH 1 13 0
28 Level2 B FIRST 0 0 0
29 Level2 B SECOND 3 9 0
30 Level2 B THIRD 5 85 0
31 Level2 B FOURTH 4 96 0
32 Level2 B FIFTH 3 40 0
33 Level2 B SIXTH 0 17 0
34 Level3 A FIRST 2 0 0
35 Level3 A SECOND 1 9 0
36 Level3 A THIRD 3 7 0
37 Level3 A FOURTH 9 18 0
38 Level3 A FIFTH 1 22 0
39 Level3 A SIXTH 1 13 0
40 Level3 B FIRST 0 0 0
41 Level3 B SECOND 3 9 0
42 Level3 B THIRD 5 85 0
43 Level3 B FOURTH 4 96 0
44 Level3 B FIFTH 3 40 0
45 Level3 B SIXTH 0 17 0
我想要的结果是：
Flag1 Flag2 Flag3 Type1 Type2 Type3 Sum
1 Level1 A FIRST 2 0 0 2
2 Level1 A SECOND 1 9 0 12
3 Level1 A THIRD 3 7 0 22
4 Level1 A FOURTH 9 18 0 49
5 Level1 A FIFTH 1 22 0 72
6 Level1 A SIXTH 1 13 0 86
7 Level1 B FIRST 0 0 0 0
8 Level1 B SECOND 3 9 0 12
9 Level1 B THIRD 5 85 0 102
10 Level1 B FOURTH 4 96 0 202
11 Level1 B FIFTH 3 40 0 245
12 Level1 B SIXTH 0 17 0 262
13 Level1 (all) FIRST 2 0 0 2
14 Level1 (all) SECOND 4 18 0 24
15 Level1 (all) THIRD 8 92 0 124
16 Level1 (all) FOURTH 13 114 0 251
17 Level1 (all) FIFTH 4 62 0 317
18 Level1 (all) SIXTH 1 30 0 348
19 Level1 A (all) 17 68 0 85
20 Level1 B (all) 15 247 0 262
21 Level1 (all) (all) 32 315 0 347
22 Level2 A FIRST 2 0 0 2
23 Level2 A SECOND 1 9 0 12
24 Level2 A THIRD 3 7 0 22
25 Level2 A FOURTH 9 18 0 49
26 Level2 A FIFTH 1 22 0 72
27 Level2 A SIXTH 1 13 0 86
28 Level2 B FIRST 0 0 0 0
29 Level2 B SECOND 3 9 0 12
30 Level2 B THIRD 5 85 0 102
31 Level2 B FOURTH 4 96 0 202
32 Level2 B FIFTH 3 40 0 245
33 Level2 B SIXTH 0 17 0 262
34 Level2 (all) FIRST 2 0 0 2
35 Level2 (all) SECOND 4 18 0 24
36 Level2 (all) THIRD 8 92 0 124
37 Level2 (all) FOURTH 13 114 0 251
38 Level2 (all) FIFTH 4 62 0 317
39 Level2 (all) SIXTH 1 30 0 348
40 Level2 A (all) 17 68 0 85
41 Level2 B (all) 15 247 0 262
42 Level2 (all) (all) 32 315 0 347
43 Level3 A FIRST 2 0 0 2
44 Level3 A SECOND 1 9 0 12
45 Level3 A THIRD 3 7 0 22
46 Level3 A FOURTH 9 18 0 49
47 Level3 A FIFTH 1 22 0 72
48 Level3 A SIXTH 1 13 0 86
49 Level3 B FIRST 0 0 0 0
50 Level3 B SECOND 3 9 0 12
51 Level3 B THIRD 5 85 0 102
52 Level3 B FOURTH 4 96 0 202
53 Level3 B FIFTH 3 40 0 245
54 Level3 B SIXTH 0 17 0 262
55 Level3 (all) FIRST 2 0 0 2
56 Level3 (all) SECOND 4 18 0 24
57 Level3 (all) THIRD 8 92 0 124
58 Level3 (all) FOURTH 13 114 0 251
59 Level3 (all) FIFTH 4 62 0 317
60 Level3 (all) SIXTH 1 30 0 348
61 Level3 A (all) 17 68 0 85
62 Level3 B (all) 15 247 0 262
63 Level3 (all) (all) 32 315 0 347
64 (all) A FIRST 6 0 0 6
65 (all) A SECOND 9 27 0 42
66 (all) A THIRD 18 48 0 108
67 (all) A FOURTH 45 102 0 255
68 (all) A FIFTH 48 168 0 471
69 (all) A SIXTH 51 207 0 729
70 (all) B FIRST 0 0 0 0
71 (all) B SECOND 9 27 0 36
72 (all) B THIRD 24 282 0 342
73 (all) B FOURTH 36 570 0 948
74 (all) B FIFTH 45 690 0 1683
75 (all) B SIXTH 45 741 0 2469
76 (all) A (all) 51 552 0 1611
77 (all) B (all) 45 2310 0 5478
78 (all) (all) (all) 96 2862 0 7089
由于
答案 0 :(得分：3)
目前还不清楚你想要什么，因为你提到了“聚合”和“以前”的活动，但如果你想要一个名为dfrm的数据框的colsums后面的rowums，那么这就行了：
dfrm$totals <- rowSums(dfrm[, 4:6])
dfrmT <- rbind(dfrm, data.frame(Flag1="all", Flag2="all", Flag3="all",
t( colSums(dfrm[, 4:7]) )
) )
dfrmT
编辑：所以你确实想要行总和，然后在Flag1和Flag2的级别内你想要的cumsums： （如果你想要多个小计，那就在你之前的问题中得到了解答。） R: calculating margins or row & col sums for a data frame
dfrmT$CS <- ave( dfrmT$totals, list(dfrmT$Flag1, dfrmT$Flag2), FUN=cumsum)
dfrmT
Flag1 Flag2 Flag3 Type1 Type2 Type3 totals CS
1 Level1 A FIRST 2 0 0 2 2
2 Level1 A SECOND 1 9 0 10 12
3 Level1 A THIRD 3 7 0 10 22
4 Level1 A FOURTH 9 18 0 27 49
5 Level1 A FIFTH 1 22 0 23 72
6 Level1 A SIXTH 1 13 0 14 86
7 Level1 B FIRST 0 0 0 0 0
8 Level1 B SECOND 3 9 0 12 12
9 Level1 B THIRD 5 85 0 90 102
10 Level1 B FOURTH 4 96 0 100 202
11 Level1 B FIFTH 3 40 0 43 245
12 Level1 B SIXTH 0 17 0 17 262
22 Level2 A FIRST 2 0 0 2 2
23 Level2 A SECOND 1 9 0 10 12
24 Level2 A THIRD 3 7 0 10 22
25 Level2 A FOURTH 9 18 0 27 49
26 Level2 A FIFTH 1 22 0 23 72
27 Level2 A SIXTH 1 13 0 14 86
28 Level2 B FIRST 0 0 0 0 0
29 Level2 B SECOND 3 9 0 12 12
30 Level2 B THIRD 5 85 0 90 102
31 Level2 B FOURTH 4 96 0 100 202
32 Level2 B FIFTH 3 40 0 43 245
33 Level2 B SIXTH 0 17 0 17 262
34 Level3 A FIRST 2 0 0 2 2
35 Level3 A SECOND 1 9 0 10 12
36 Level3 A THIRD 3 7 0 10 22
37 Level3 A FOURTH 9 18 0 27 49
38 Level3 A FIFTH 1 22 0 23 72
39 Level3 A SIXTH 1 13 0 14 86
40 Level3 B FIRST 0 0 0 0 0
41 Level3 B SECOND 3 9 0 12 12
42 Level3 B THIRD 5 85 0 90 102
341 all all all 89 795 0 884 884
另一方面，如果你希望每个Type中的cumsums在新Flag1和Flag2分区初始化，那么：
ave( dfrm[ , grep("Type", names(dfrm))], list(dfrm$Flag1, dfrm$Flag2), FUN=cumsum)
Type1 Type2 Type3
1 2 0 0
2 3 9 0
3 6 16 0
4 15 34 0
5 16 56 0
6 17 69 0
7 0 0 0
8 3 9 0
9 8 94 0
10 12 190 0
11 15 230 0
12 15 247 0
22 2 0 0
23 3 9 0
24 6 16 0
25 15 34 0
26 16 56 0
27 17 69 0
28 0 0 0
29 3 9 0
30 8 94 0
31 12 190 0
32 15 230 0
33 15 247 0
34 2 0 0
35 3 9 0
36 6 16 0
37 15 34 0
38 16 56 0
39 17 69 0
40 0 0 0
41 3 9 0
42 8 94 0
这适用于cbind（） - 转到dfrm但需要处理名称（）：
dfrmCS <- cbind(dfrm, ave( dfrm[ , grep("Type", names(dfrm))],
list(dfrm$Flag1, dfrm$Flag2), FUN=cumsum) )
names(dfrmCS)[8:10] <- paste(names(dfrmCS)[8:10], "CS", sep="_")