Question

我有两张这样的表： -

表A

ITEM    LOCATION    CODE
A       WHS         QW123
B       WHS         QW124
C       WHS         QW125

表B

ATR_NO          ITEM    CODE    ATT_ID  ATT_VALUE
20110101123310  A   QW123   SIZE    24
20110101123310  A   QW123   GRADE   2
20110101123351  B   QW124   SIZE    20
20110101123351  B   QW124   GRADE   3
20110101124042  C   QW125   SIZE    26
20110101124042  C   QW125   GRADE   4
20110101131210  A   QW123   SIZE    26
20110101131210  A   QW123   GRADE   1
20110101144542  C   QW125   SIZE    27
20110101144542  C   QW125   GRADE   1

使用SQL shold的预期结果如下所示： -

结果

ITEM    LOCATION    CODE    SIZE    GRADE
A       WHS         QW123   26  1
B       WHS         QW124   20  3
C       WHS         QW125   27  1

我怎样才能做到这一点？

Answer 1

获取每件商品的最新ATR_NO，将其与表b连接两次以获得尺寸和等级：

select
  a.ITEM, a.LOCATION, a.CODE, SIZE = b1.ATT_VALUE, GRADE = b2.ATT_VALUE
from
  [TABLE A] a
  inner join (select max(ATR_NO) from [TABLE B] group by ITEM) i on i.ITEM = a.ITEM
  inner join [TABLE B] b1 on b1.ATR_NO = i.ATR_NO and b1.ATT_ID = 'SIZE'
  inner join [TABLE B] b2 on b2.ATR_NO = i.ATR_NO and b2.ATT_ID = 'GRADE'
order by
  a.ITEM

如何提取最新记录

1 个答案: