这是我的数据。会员可以多次注册并可以随时更改计划,我需要获取C_level数据,以获取ID为1的“8/1/2017”的最新版本,因为ID 2没有最新数据,我们必须显示12/31/2016记录。
ID Start_Date End_Date C_Level
1 1/1/2016 12/31/2016 1
1 1/1/2017 8/1/2017 2
1 9/1/2017 12/31/2017 3
1 1/1/2018 12/31/2018 0
2 1/1/2015 12/31/2015 2
2 1/1/2016 12/31/2016 3
答案 0 :(得分:1)
如果我理解您的要求,那么此查询应该提供您想要的内容:
WITH current_running AS (
SELECT to_date( '8/1/2017','mm/dd/rrrr') As Current_running_date
FROM dual
)
SELECT * FROM (
SELECT t.*,
row_number() Over (partition by id order by end_date desc ) As rn,
c.Current_running_date
FROM Table1 t
JOIN current_running c
ON c.Current_running_date >= ANY( t.Start_Date, t.End_Date )
)
WHERE rn = 1
;
演示:http://api.jquery.com/toggle/
对于current_running_date = 2017-08-01
,它给出:
| ID | START_DATE | END_DATE | C_LEVEL | RN | CURRENT_RUNNING_DATE |
|----|-----------------------|-----------------------|---------|----|----------------------|
| 1 | 2017-01-01 00:00:00.0 | 2017-08-01 00:00:00.0 | 2 | 1 | 2017-08-01T00:00:00Z |
| 2 | 2016-01-01 00:00:00.0 | 2016-12-31 00:00:00.0 | 3 | 1 | 2017-08-01T00:00:00Z |
而对于current_running_date = 2016-07-15
| ID | START_DATE | END_DATE | C_LEVEL | RN | CURRENT_RUNNING_DATE |
|----|-----------------------|-----------------------|---------|----|----------------------|
| 1 | 2016-01-01 00:00:00.0 | 2016-12-31 00:00:00.0 | 1 | 1 | 2016-07-15T00:00:00Z |
| 2 | 2016-01-01 00:00:00.0 | 2016-12-31 00:00:00.0 | 3 | 1 | 2016-07-15T00:00:00Z |