Question

我正在使用SQL Ser 2008并且只有一列数据的大表。数据是随机字符串，几乎没有一致性。例如：名称帐户445566 0010020056893010445478008 AFD 369.我一直在使用stackoverflow用户建议的拆分功能。它工作得很好，但该函数将拆分字符串分配到一列。我需要一排单独的列。目前的结果是1col，其值为Name，Account，445566，...但是我要找的结果是col1 Name，col2 Account，col3 445566，... 如果有人能够提供一些有关如何定制此脚本或其用途以获得所需结果的见解，那将非常感激。

CREATE FUNCTION [dbo].[Split] 
(    
 @String varchar(max) 
,@Delimiter char 
) 
RETURNS @Results table 
( 
 Ordinal int 
,StringValue varchar(max) 
) 
as 
begin 

set @String = isnull(@String,'') 
set @Delimiter = isnull(@Delimiter,'') 

declare 
 @TempString varchar(max) = @String 
,@Ordinal int = 0 
,@CharIndex int = 0 

set @CharIndex = charindex(@Delimiter, @TempString) 
while @CharIndex != 0 begin      
    set @Ordinal += 1        
    insert @Results values 
    ( 
     @Ordinal 
    ,substring(@TempString, 0, @CharIndex) 
    )        
    set @TempString = substring(@TempString, @CharIndex + 1, len(@TempString) - @CharIndex)      
    set @CharIndex = charindex(@Delimiter, @TempString) 
end 

if @TempString != '' begin 
    set @Ordinal += 1  
    insert @Results values 
    ( 
     @Ordinal 
    ,@TempString 
    ) 
end 

return 
end 

--The usage:
SELECT    
* 
FROM    
mytable M    
CROSS APPLY    
[dbo].[Split] (M.TheColumn, ' ') S
Where rtrim(s.StringValue) != ''

Answer 1

如果您知道字符串中有6列，则可以使用看起来像这样的拆分函数，当然也可以将函数修改为您想要的任意数量的列。函数不能返回动态数量的列。

create function dbo.Split6(@String varchar(max), @Delimiter char(1)) 
returns table as return
(
  select
    substring(T.Col, 1, S1.Pos-1) as Col1,
    substring(T.Col, S1.Pos+1, S2.Pos-S1.Pos-1) as Col2,
    substring(T.Col, S2.Pos+1, S3.Pos-S2.Pos-1) as Col3,
    substring(T.Col, S3.Pos+1, S4.Pos-S3.Pos-1) as Col4,
    substring(T.Col, S4.Pos+1, S5.Pos-S4.Pos-1) as Col5,
    substring(T.Col, S5.Pos+1, S6.Pos-S5.Pos-1) as Col6
  from (select @String+replicate(@Delimiter, 6)) as T(Col)
    cross apply (select charindex(@Delimiter, T.Col, 1)) as S1(Pos)
    cross apply (select charindex(@Delimiter, T.Col, S1.Pos+1)) as S2(Pos)
    cross apply (select charindex(@Delimiter, T.Col, S2.Pos+1)) as S3(Pos)
    cross apply (select charindex(@Delimiter, T.Col, S3.Pos+1)) as S4(Pos)
    cross apply (select charindex(@Delimiter, T.Col, S4.Pos+1)) as S5(Pos)
    cross apply (select charindex(@Delimiter, T.Col, S5.Pos+1)) as S6(Pos)
)

测试：

declare @T table (Col varchar(100))

insert into @T values
 ('Name Account 445566 0010020056893010445478008 AFD 369'),
 (''),
 ('1 2'),
 ('1  3')

select S.Col1, S.Col2, S.Col3, S.Col4, S.Col5, S.Col6
from @T as T
  cross apply
    dbo.Split6(T.Col, ' ') as S

结果：

Col1  Col2     Col3    Col4                       Col5  Col6
----  -------  ------  -------------------------  ----  ----
Name  Account  445566  0010020056893010445478008  AFD   369

1     2             
1              3

Answer 2

您可以尝试使用PIVOT。

http://msdn.microsoft.com/en-us/library/ms177410.aspx

SQL Server 2008 T-SQL UDF Split（）裁剪

2 个答案: