Question

我有一个3列的表格。 DateRangeFields，IsOutOfTarget和AmountOfJobs。

我需要的是按DateRangeFields对结果进行分组，并显示在该日期范围内超出目标的作业百分比。数据如下所示
我试图创建一个显示数据的表，但是Stackoverflow似乎不允许这样做，所以我在Dbfiddle中创建了它。

https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=ae9ce68d96f0d88a3f78ad6987010f56

Answer 1

只需使用条件聚合：

Select DateRangeFields,
       (SUM(CASE WHEN IsOutOfTarget = 'True' THEN AmountOfJobs END) * 1.0 /
        SUM(AmountOfJobs)
       ) as ratio
From @MyTable t
Group By DateRangeFields;

Answer 2

也许不是最干净的方法，但是：

Select A.DateRangeFields, CAST(OutOfTargetJobs AS FLOAT)/CAST(OutOfTargetJobs+InTargetJobs AS FLOAT) As Percentage FROM (
Select DateRangeFields, SUM(AmountOfJobs) AS OutOfTargetJobs 
From @MyTable
Where IsOutOfTarget = 'True'
Group By DateRangeFields, IsOutOfTarget
) A
Inner Join
(
Select DateRangeFields, SUM(AmountOfJobs) AS InTargetJobs From @MyTable
Where IsOutOfTarget = 'False'
Group By DateRangeFields, IsOutOfTarget
) B on A.DateRangeFields = B.DateRangeFields;

Answer 3

怎么样：

select sum(c1) as s_c1, sum(c2) as s_c2, divide(s_c1, s_c2) as pct from tab group by c3;

divide是您可以在正式文档中找到的功能。我不确定。

对我而言，不接触SQL的时间很长。所以您知道，我上面提供的语句可能无法运行。

如何返回2列之间的百分比，该百分比由SQL中的另一列分组？

3 个答案: