Question

我有一个常规表[customer_table]，其中包含一些看起来像这样的空值

id | customer | country | col0 | col1 | col2 |
==============================================
1  | foo      | USA     | NULL | foo  | bar  | 
2  | bar      | USA     | foo  | NULL | foo  | 
3  | foo2     | CANADA  | bar  | col1 | NULL | 
4  | bar2     | GERMANY | foo  | NULL | bar  | 
5  | bar3     | CANADA  | foo  | foo  | bar  | 
6  | bar4     | UK      | bar  | foo  | bar  | 
7  | bar5     | UK      | bar  | bar  | bar  |

我想计算按国家/地区分组的各列的非空值的百分比

country | col0%  | col1% | col2% |
==================================
USA     | 50%    | 50%  | 100%   |
GERMANY | 100%   | 0%   | 100%   |
CANADA  | 100%   | 100% | 50%    |
UK      | 100%   | 100% | 100%   |

这就是我想要的

select TOTAL.[country],
[count_col0]*100/[count_total] as [col0%],
[count_col1]*100/[count_total] as [col1%]
from (
    (select [country], COUNT(*) as [count_total] from [customer_table]
     where [country] <> '' group by [country]) TOTAL
    left join
     (select [country], COUNT(*) as [count_col0] from [customer_table] 
     where [country] <> '' and [col0] <> '' group by [country]) T_COL0
     on T_COL0.[country] = TOTAL.[country]
    left join 
     (select [country], COUNT(*) as [count_col1] from [customer_table] 
     where [country] <> '' and [col1] <> '' group by [country]) T_COL1
     on T_COL1.[country] = TOTAL.[country]
)

它可以工作，但是我有很多专栏文章，我认为这不是一个很好的解决方案

Answer 1

只使用聚合。最简单的方法是：

select country,
       count(col1) * 1.0 / count(*),
       count(col2) * 1.0 / count(*),
       count(col3) * 1.0 / count(*)
from customertable
group by country

Answer 2

DECLARE @customertable TABLE (country NVARCHAR(100), col1 BIGINT, col2 BIGINT, col3 BIGINT)

INSERT INTO @customertable 
(country, col1, col2, col3)
    VALUES 
    (N'USA', 0, null, 0)
    ,(N'USA', 0, null, 0)
    ,(N'USA', null, null, 0)
    ,(N'USA', 0, 0, null)
    , (N'CA', 0, null, 0)
    ,(N'CA', 0, null, 0)
    ,(N'CA', null, null, 0)
    ,(N'CA', 0, 0, null)
;WITH DistinctCountries AS (
SELECT DISTINCT Country
FROM @customertable
)

SELECT Country
, col1/(total*1.0) as [col1pct]
, col2/(total*1.0) as [col2pct]
, col3/(total*1.0) as [col3pct]
FROM DistinctCountries AS DistinctCountries
OUTER APPLY (
SELECT 
  SUM(CASE WHEN col1 IS NULL THEN 0 ELSE 1 END) col1
  ,SUM(CASE WHEN col2 IS NULL THEN 0 ELSE 1 END) col2
  ,SUM(CASE WHEN col3 IS NULL THEN 0 ELSE 1 END) col3
  ,COUNT(1) as Total
FROM @customertable AS CountApply
WHERE CountApply.Country = DistinctCountries.Country
)MainCount

如果您有一个独特的国家/地区列表，则最好这样做。

如果您有很多列，最好创建一个动态SQL查询以自动创建每个CASE并将其标记化..或..一个动态数据透视查询。

Answer 3

您要在此处查找COUNT（DISTINCT xxx）/ COUNT（*）模式。

现在，当您有很多要覆盖的列时，可以在INFORMATION_SCHEMA.COLUMNS系统表中查找它们并生成您要像这样运行的查询：

SELECT
  'SELECT country'
UNION ALL
SELECT
      CONCAT(', (100 * COUNT(DISTINCT ', COLUMN_NAME, ')) / COUNT(*) AS [', COLUMN_NAME, '%]')
FROM  INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'customer_table'
      AND TABLE_SCHEMA = 'dbo'
      AND COLUMN_NAME NOT IN ('id', 'customer', 'country')
UNION ALL
SELECT
  'FROM dbo.customer_table GROUP BY country;'

这将导致：

SELECT country
, (100 * COUNT(DISTINCT col0)) / COUNT(*) AS [col0%]
, (100 * COUNT(DISTINCT col1)) / COUNT(*) AS [col1%]
, (100 * COUNT(DISTINCT col2)) / COUNT(*) AS [col2%]
FROM dbo.customer_table GROUP BY country;

计算由另一列分组的表中每一列的非空百分比或行

3 个答案: