Question

我有一些问题矩阵：

b=   [[-2.5,  0.5],        #b is random matrix
     [-1.5, -0.5],
     [-0.5,  0.5]]

如何从b获得：

b=[[[-2.5], [0.5]], [[-1.5], [-0.5]], [[-0.5], [0.5]]]

非常感谢

Answer 1

>>> b=   [[-2.5,  0.5],        #b is random matrix
     [-1.5, -0.5],
     [-0.5,  0.5]]
>>> [[[val] for val in row] for row in b]
[[[-2.5], [0.5]], [[-1.5], [-0.5]], [[-0.5], [0.5]]]

说明：考虑一个清单：

>>> oned = [1, 2, 3]

您可以使用列表解析重新创建它：

>>> [val for val in oned] 
[1, 2, 3]

然后将每个元素包装在自己的列表中：

>>> [[val] for val in oned]
[[1], [2], [3]]

将其扩展到两个维度。

Answer 2

Claudiu's answer可能更直接，但这里有一个替代解决方案，递归遍历任何深度的列表列表。

>>> listify = lambda x: map(listify, x) if isinstance(x, list) else [x]
>>> listify(b)
[[[-2.5], [0.5]], [[-1.5], [-0.5]], [[-0.5], [0.5]]]

Python矩阵，行和列

2 个答案: