Question

使用sqlalchemy.func.rownumber().over生成 PARTITION BY 时，如何将其更改为 ORDER BY 。

query = session.query(
    sqlalchemy.func.row_number().over(Record.id).label('#'),
    Record.id,
    Record.state,
).filter(
    Record.state == "new"
)

sqlalchemy.engine.base.Engine使用 PARTITION BY

生成

SELECT row_number() OVER (PARTITION BY records.pk) AS "#", records.pk AS records_pk, records.state AS records_state
FROM records 
WHERE records.state = %(state_1)s

Answer 1

我相信over()函数应该使用order_by参数：

query = session.query(
    sqlalchemy.func.row_number().over(order_by=Record.id).label('#')
    Record.id,
    Record.state,
).filter(
    Record.state == "new"
)

Answer 2

您可以简单地执行以下操作：

select records.pk AS records_pk, records.state AS records_state
FROM records 
WHERE records.state = %(state_1)s
Group by records.pk, records.state
order by records.pk, records.state

使用分组依据。 GROUP BY子句是聚合的，而PARTITION BY子句是解析的。

使用ORDER BY代替PARTION BY row_number（）。over（）

2 个答案: