Question

使用Jupyter Notebook，我的代码曾经运行得很好，直到我决定在寻找二次方程式的根时，将虚数的输出以“ i”表示。一个问题是：

from ipykernel import kernelapp as app

和

 LookupError                               Traceback (most recent call last)
cell_name in async-def-wrapper()

cell_name in Noroots(a, b, c)

LookupError: unknown encoding: i

下面是代码。

import numpy as np
def equalroots(a,b,c):
        print("There are two real and equal roots")
        print("Since they are the same,we have one output")
        print(((-b)+(np.sqrt((b**2)-(4*a*c))))/(2*a))

def differroots(a,b,c):
        print("There are two real and distinct roots")
        print("The roots are {:f} and {:f}".format(((-b)+(np.sqrt((b**2)-(4*a*c))))/(2*a),((b)+(np.sqrt((b**2)-(4*a*c))))/(2*a)))
def Noroots(a,b,c):
    print("There are no real roots.Imaginary roots")
    print(str(((-b)+(np.sqrt((b**2)-(4*a*c))))/(2*a)),"i and ",str(((b)+(np.sqrt((b**2)-(4*a*c))))/(2*a),"i"))

print("Please enter the function in cordination with a(x**2)+bx+c")        
a=float(input("Please Input the value of a : "))  
b=float(input("Please Input the value of b : ")) 
c=float(input("Please Input the value of c : ")) 

if (b**2)-(4*a*c)==0:
    return(equalroots(a,b,c))
elif (b**2)-(4*a*c)>0:
    return(differroots(a,b,c))
else:
    return(Noroots(a,b,c))

LookupError。我在显示虚数时遇到问题

0 个答案: