Question

我有一个名为employee_salary的表，其中有两列（emp_id，emp_salary）。

我需要从此表中获取第3个最低emp_salary。在这种情况下，应该是我的查询，以便我可以得到确切的值。

Answer 1

这可能是一个解决方案

select top 1 * from
(
    select top 3 * from
    (
     select distinct  emp_sal from employee order by asc emp_sal
    ) d orderby desc emp_sal
)

Answer 2

我在Postgres数据库中对此进行了测试。我希望这个查询适用于所有类型的数据库。请试试这个。

select emp_salary from emp_salary group by emp_salary order by emp_salary limit 1 offset 2;

Answer 3

SELECT TOP 1 * FROM employee_salary WHERE emp_salary in（SELECT TOP 3 emp_salary FROM employee_salary ORDER BY emp_salary）ORDER BY emp_salary DESC

但是，这并不适用于所有数据库。你需要找出替代方案。例如。在Informix中，语句将为SELECT FIRST 1 *

Answer 4

使用窗口函数......此构造用于SQL Server：

;WITH CTE AS
(
SELECT ..., ROW_NUMBER() OVER (ORDER BY emp_salary) AS rn
FROM myTable
)
SELECT ...
FROM CTE
WHERE rn = 3

Answer 5

您可以使用RANK () function in SQL Server

获得相同的工资

;WITH CTE AS
(
SELECT ..., RANK() OVER (ORDER BY emp_salary) AS rn
FROM myTable
)
SELECT ...
FROM CTE
WHERE rn = 3

Answer 6

我通过在sql server 2008中执行以下查询得到了答案

Select MIN(emp_salary) from MyTable Where emp_salary in 
(Select DISTINCT TOP 3 emp_salary from MyTable order by 1 DESC)

我得到了第3个最低值。

DISTINCT用于当一个或多个薪水相同时。

Answer 7

select * from table_name where col_name = (select (min(col_name) from table_name where col_name > (select min(col_name) from table_name where col_name > (select min(col_name) from table_name)));

Sql查询获取第3个最低值

7 个答案: