将找到第二低值的mysql查询转换为sqlite查询

Question

我获得了一个查询语句，该语句找到比较多列的第二低值，并将结果返回到名为＆＃39; 2nd_lowest＆＃39;的另一列中。该查询适用于MYSQL。我想在sqlite数据库中得到相同的结果，但sqlite不支持该查询。如何将mysql查询转换为sqlite查询...查询如下：

with num(x) as(
  values(1),(2),(3),(4),(5)
),
new as(
 select name, case x when 1 then score1  when 2 then score2  when 3 then score3
                     when 4 then score4  else score5 end val
   from test, num
  where val!=min(score1,score2,score3,score4,score5)
)
update test set "2nd_lowest"=
   (select min(val) from new where new.name=test.name)

我有这个sqlite查询，但我收到异常错误

update test set 2nd_lowest=(select min(val) from "
             + "( select case x when 1 then score1 when 2 then score2 when 3 then score3 when 4 then score4 else score5 end val from test T, "
             + "(select 1 as x union all values (2),(3),(4),(5))X where val!=min(score1,score2,score3,score4,score5)" +
               " and T.name=test.name ))

，异常错误是 -

java.sql.SQLException:near"values":syntax error

当我改变＆＃39;值条款＆＃39;选择子句，如下例所示：

update test set 2nd_lowest=(select min(val) from "
                 + "( select case x when 1 then score1 when 2 then score2 when 3 then score3 when 4 then score4 else score5 end val from test T, "
                 + "(select 1 as x union all select (2),(3),(4),(5))X where val!=min(score1,score2,score3,score4,score5)" +
                   " and T.name=test.name ))<br/>

我得到了这个例外：

Java.sql.SQLException: SELECTs to the left and right of UNION ALL do not have the same number of result columns <br/>

请所有帮助将不胜感激。谢谢。