我有两个形状完全不同的数据帧(df1,df2):df1:(64,6); df2:(564,9)。
df1包含一列(df1.objectdesc),该列的值(字符串)也可以在df2(df2.objdescription)的列中找到。由于两个数据框的形状不同,因此我必须使用.isin()
来获取匹配的值。然后,我想从恰好匹配并添加到df1的那些行中,从df2的另一列(df2.idname)中获取第三个值。
示例数据集:
df1
Content objectdesc TS_id
0 sdrgs 1_OG.Raum45 55
1 sdfg 2_OG.Raum23 34
2 psdfg GG.Raum12 78
3 sdfg 1_OG.Raum98 67
df2:
Numb_val object_count objdescription min idname
0 463 9876 1_OG_Raum76 1 wq19
1 251 8324 2_OG.Raum34 9 zt45
2 456 1257 1_OG.Raum45 4 bh34
3 356 1357 2_OG.Raum23 3 if32
4 246 3452 GG.Raum12 5 lu76
5 345 8553 1_OG.Raum98 8 pr61
预期输出:
Content objectdesc TS_id idname
0 sdrgs 1_OG.Raum45 55 bh34
1 sdfg 2_OG.Raum23 34 if32
2 psdfg GG.Raum12 78 lu76
3 sdfg 1_OG.Raum98 67 pr61
到目前为止,这是我的代码:
def get_id(x, y):
for values in x,y:
if x['objectdesc'].isin(y['objdescription']).any() == True:
return y['idname']
df1['idname'] = get_id(df1, df2)
不幸的是,这仅提供了从索引0开始的df2['idname']
的值,而没有真正给我匹配行中的值。
感谢您的帮助。谢谢!
答案 0 :(得分:1)
您可以将两者合并。
from io import StringIO
import pandas as pd
df_1_str = \
'''
Content objectdesc TS_id
sdrgs 1_OG.Raum45 55
sdfg 2_OG.Raum23 34
psdfg GG.Raum12 78
sdfg 1_OG.Raum98 67
'''
df_2_str = \
'''
Numb_val object_count objdescription min idname
463 9876 1_OG_Raum76 1 wq19
251 8324 2_OG.Raum34 9 zt45
456 1257 1_OG.Raum45 4 bh34
356 1357 2_OG.Raum23 3 if32
246 3452 GG.Raum12 5 lu76
345 8553 1_OG.Raum98 8 pr61
'''
df_1 = pd.read_csv(StringIO(df_1_str), header=0, delim_whitespace=True)
df_2 = pd.read_csv(StringIO(df_2_str), header=0, delim_whitespace=True)
df_3 = df_1.merge(df_2[['objdescription', 'idname']], left_on='objectdesc',
right_on='objdescription').drop('objdescription', axis='columns')
df_3
的内容:
Content objectdesc TS_id idname
-- --------- ------------ ------- --------
0 sdrgs 1_OG.Raum45 55 bh34
1 sdfg 2_OG.Raum23 34 if32
2 psdfg GG.Raum12 78 lu76
3 sdfg 1_OG.Raum98 67 pr61
答案 1 :(得分:0)
可以尝试以下方法:
df1.merge(df2, left_on='objectdesc', right_on='objdescription')[['Content', 'objectdesc', 'TS_id', 'idname']]
参考:
https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.merge.html