Django:接下来30天每天的总生日

时间:2011-05-09 12:36:52

标签: django django-models django-queryset

我有一个类似的模型:

class Person(models.Model):
    name = models.CharField(max_length=40)
    birthday = DateTimeField() # their next birthday

我想获得接下来30天每天总生日的列表。例如,列表看起来像这样:

[[9, 0], [10, 3], [11, 1], [12, 1], [13, 5], ... #30 entries in list 

列表中的每个列表条目都是日期编号,后跟当天的生日数。例如,5月9日有0个生日。

更新

我的数据库是sqlite3 - 将来会转移到postgres。

4 个答案:

答案 0 :(得分:4)

from django.db.models import Count
import datetime
today = datetime.date.today()
thirty_days = today + datetime.timedelta(days=30)
birthdays = dict(Person.objects.filter(
                    birthday__range=[today, thirty_days]
                 ).values_list('birthday').annotate(Count('birthday')))


for day in range(30):
    date = today + datetime.timedelta(day)
    print "[%s, %s]" % (date, birthdays.get(date, 0))

答案 1 :(得分:2)

我会以这种方式获得日期和生日列表:

from datetime import date, timedelta    
today = date.today()
thirty_days = today + timedelta(days=30)

# get everyone with a birthday
people = Person.objects.filter(birthday__range=[today, thirty_days])

birthday_counts = []
for date in [today + timedelta(x) for x in range(30)]:
    # use filter to get only birthdays on given date's day, use len to get total
    birthdays = [date.day, len(filter(lambda x: x.birthday.day == date.day, people))]
    birthday_counts.append(birthdays)

答案 2 :(得分:0)

像这样 -

from datetime import date, timedelta

class Person(models.Model):
    name = models.CharField(max_length=40)
    birthday = models.DateField()

    @staticmethod
    def upcoming_birthdays(days=30):
        today = date.today()
        where = 'DATE_ADD(birthday, INTERVAL (YEAR(NOW()) - YEAR(birthday)) YEAR) BETWEEN DATE(NOW()) AND DATE_ADD(NOW(), INTERVAL %S DAY)'
        birthdays = Person.objects.extra(where=where, params=[days]).values_list('birthday', flat=True)
        data = []
        for offset in range(0, days):
            i = 0
            d = today + timedelta(days=offset)
            for b in birthdays:
                if b.day == d.day and b.month == d.month:
                    i += 1
            data.append((d.day, i))
        return data

print Person.upcoming_birthdays()

答案 3 :(得分:0)

(在接下来的X天内有生日的人的查询集) 找到很酷的解决方案! 对我来说它有效!

from datetime import datetime, timedelta
import operator

from django.db.models import Q

def birthdays_within(days):

    now = datetime.now()
    then = now + timedelta(days)

    # Build the list of month/day tuples.
    monthdays = [(now.month, now.day)]
    while now <= then:
        monthdays.append((now.month, now.day))
        now += timedelta(days=1)

    # Tranform each into queryset keyword args.
    monthdays = (dict(zip(("birthday__month", "birthday__day"), t)) 
                 for t in monthdays)


    # Compose the djano.db.models.Q objects together for a single query.
    query = reduce(operator.or_, (Q(**d) for d in monthdays))

    # Run the query.
    return Person.objects.filter(query)

但是它会列出在日期范围内生日的人。你应该改变一下。