Question

这很奇怪

当我尝试使用以下代码在后台使用RX处理文件

// this code lies in a RX statement
FirebaseStorage
    .getInstance()
    .getReference(path) // file path. which does not exist
    .getDownloadUrl()
    .addOnCompleteListener(task -> {
        if (task.isSuccessful() && task.getResult() != null) {
            String url = task.getResult().toString();
            MyLogger.logMessage(TAG, url);
            // here i have some logic to handle file 
        } else {
            MyLogger.logError(TAG, "error getting url : " + task.getException());
            emitter.onError(new Throwable(task.getException()));
        }
    });

它引发以下错误，应用程序崩溃。

2019-12-14 13:29:26.835 327-918/com E/StorageException: StorageException has occurred.
    Object does not exist at location.
     Code: -13010 HttpResult: 404
2019-12-14 13:29:26.837 327-918/com E/StorageException: {  "error": {    "code": 404,    "message": "Not Found.  Could not get object",    "status": "GET_OBJECT"  }}
    java.io.IOException: {  "error": {    "code": 404,    "message": "Not Found.  Could not get object",    "status": "GET_OBJECT"  }}
        at com.google.firebase.storage.network.NetworkRequest.parseResponse(com.google.firebase:firebase-storage@@19.0.0:438)
        at com.google.firebase.storage.network.NetworkRequest.parseErrorResponse(com.google.firebase:firebase-storage@@19.0.0:455)
        at com.google.firebase.storage.network.NetworkRequest.processResponseStream(com.google.firebase:firebase-storage@@19.0.0:446)
        at com.google.firebase.storage.network.NetworkRequest.performRequest(com.google.firebase:firebase-storage@@19.0.0:279)
        at com.google.firebase.storage.network.NetworkRequest.performRequest(com.google.firebase:firebase-storage@@19.0.0:293)
        at com.google.firebase.storage.internal.ExponentialBackoffSender.sendWithExponentialBackoff(com.google.firebase:firebase-storage@@19.0.0:70)
        at com.google.firebase.storage.internal.ExponentialBackoffSender.sendWithExponentialBackoff(com.google.firebase:firebase-storage@@19.0.0:62)
        at com.google.firebase.storage.GetDownloadUrlTask.run(com.google.firebase:firebase-storage@@19.0.0:74)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1162)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:636)
        at java.lang.Thread.run(Thread.java:764)

当我在主线程上执行相同的操作时，它会引发错误，但应用程序不会崩溃

我知道代码是完美的。

我还尝试实现不同的成功和失败侦听器，但没有发生相同的事情。

我知道该文件在该位置不存在。

我不在乎文件，但在处理错误。

即使我正确处理了错误，为什么应用也会崩溃？

这个问题已经被问到了，但是在任何地方都没有得到回答。

Firebase存储Android SDK抛出存储异常

0 个答案: