我有一个具有两个重复的实验的以下数据框。我想根据df
在每个时间戳和ID的两个副本中过滤score == 0
。
df <- data.frame(timestamp = c(1, 1, 1, 1, 2, 2, 2, 2),
ID = c(57, 57, 55, 55, 57, 57, 55, 55),
replicate= c(1, 2, 1, 2, 1, 2, 1, 2),
score = c(0, 1, 0, 0, 0, 1, 0, 0))
例如所需的输出将是:
target <- data.frame(timestamp = c(1, 1, 2, 2),
ID = c(55, 55, 55, 55),
replicate = c(1, 2, 1, 2),
score = c(0, 0, 0, 0))
我想出了一个双循环的解决方案,这种解决方案很简单,而且很可能效率很低:
tsvec <- df$timestamp %>% unique
idvec <- df$ID %>% unique
df_out <- c()
for(i in seq_along(tsvec)){ # loop along timestamps
innerdat <- df %>% filter(timestamp == tsvec[i])
for(j in seq_along(idvec)){ # loop along IDs
innerdat2 <- innerdat %>% filter(ID == idvec[j])
if(sum(innerdat2$score) == 0){
df_out <- rbind(df_out, innerdat2)
} else {
NULL
}
}
}
有人有dplyr
方式来提高效率吗?
答案 0 :(得分:3)
library(dplyr)
df %>% group_by(ID) %>% filter(all(score==0))
# A tibble: 4 x 4
# Groups: ID [1]
timestamp ID replicate score
<dbl> <dbl> <dbl> <dbl>
1 1 55 1 0
2 1 55 2 0
3 2 55 1 0
4 2 55 2 0
答案 1 :(得分:2)
使用data.table
library(data.table)
setDT(df)[, .SD[all(score == 0)], by = ID]